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VashaNatasha [74]
3 years ago
10

Find the 9th term geometric sequence 1,1/2,1/2^2w. Please show the steps.

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

9th term geometric sequence (a9) = 1 / 256

Step-by-step explanation:

Given:

Geometric sequence 1,1/2,1/2²

First term (a) = 1

Common ratio (r) = A2 / A1 = (1/2) / 1 = 1/2

Number of term (n) = 9

Find:

9th term geometric sequence (a9)

Computation:

an = ar^{n-1}

a9 = ar⁹⁻¹

a9 = (1)(1/2)⁸

a9 = (1/2)⁸

a9 = 1/256

9th term geometric sequence (a9) = 1 / 256

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Answer:

(5x^2+4y)(5x^2-4y)

Step-by-step explanation:

25x^4-16y^2 has the form a^2-b^2 known as a difference of squares. It factors into (a+b)(a-b). To find a and b you take the square root.

\sqrt{25x^4} =5x^2

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The factored for is (a+b)(a-b).

In this case, it is (5x^2+4y)(5x^2-4y)


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3 years ago
Find the value of x.<br> 16.2<br> 0.03<br> 38.5<br> 34.8
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Hi there!

\large\boxed{x = 38.5}}

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