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3 years ago

What is the ratio (multiplier) for the following geometric sequence? 2, 0.5, 0.125, .03125...

Mathematics

1 answer:

Firlakuza [10]3 years ago

5 0

The multiplier is (1/4) or .25

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Solve the following equation <br>14 + 6x = 2

sweet-ann [11.9K]

Answer:

x=-2

Step-by-step explanation:

14+6x=2

Then u move 14 to the other side since it doesn't have a a variable and 2 doesnt also there both just numbers so 14 moved to the otehr side will be -14 so 6x=2-14

6x=-12

x=-12/6=-2

6 0

3 years ago

Read 2 more answers

The area of a rectangle is 70 m², and the length of the rectangle is 11 m less than three times the width. Find the dimensions o

11111nata11111 [884]

Step-by-step explanation:

the area of a rectangle is

length × width

in our case

length × width = 70 m²

length = 3×width - 11

we can use this second equation in the first and get

(3×width - 11) × width = 70

3×width² - 11×width - 70 = 0

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 3

b = -11

c = -70

x = (11 ± sqrt((-11)² - 4×3×-70))/(2×3) =

= (11 ± sqrt(121 + 840))/6 =

= (11 ± sqrt(961))/6

x1 = (11 + 31)/6 = 42/6 = 7

x2 = (11 - 31)/6 = -20/6 = -10/3

the negative solution is not applicable for a length in an object.

so, only x1 = 7 m is our solution.

the width of the rectangle is 7 m.

the length = 3×width - 11 = 3×7 - 11 = 21-11 = 10 m

7 0

2 years ago

BRAINLIEST FOR WHOEVER ANSWERS FIRST!!!!

Fofino [41]

Answer:

x = 34

Step-by-step explanation:

ΔABD and ΔBCD are both isosceles triangles

In ΔABD

AB =AD, hence ∠ABD = ∠ADB ( base angles are equal )

∠ABD = $\frac{180-44}{2}$ = $\frac{136}{2}$ = 68°

∠DBC = 180° - 68° = 112° ( straight angle )

∠BCD = x = $\frac{180-112}{2}$ = $\frac{68}{2}$ = 34

4 0

3 years ago

Is -1, 6, -36, 216 geometric or not?

monitta

Yes that sequence is geometric although it’s negative

3 0

3 years ago

Prove algebraically what type of function this is (even, odd, or neither).<br>f(x) = x^6 – x^4

Savatey [412]

Let's see.

We have function $f(x)=x^6-x^4$ . We have to determine if the function is even or odd or neither.

We can find this out in many ways but the assignment specifically asks to prove this algebraically.

Function is even if $f(x)=f(-x)$ , so, $x^6-x^4=(-x)^6-(-x)^4$

Which is true since negative raised to an even power is positive to that same number.

Similarly, function is odd if $f(x)=-f(-x)$ , that is,

$x^6-x^4\neq-((-x)^6-(-x)^4)$ .

So we have prooved that function $f(x)$ is an even function not an odd function and therefore also not neither.

Hope this helps.

3 0

3 years ago