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3 years ago

What is the ratio (multiplier) for the following geometric sequence? 2, 0.5, 0.125, .03125...

Mathematics

1 answer:

Firlakuza [10]3 years ago

5 0

The multiplier is (1/4) or .25

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Question 6 of 10

Rudik [331]

If the series is A B C D then the next one is E

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3 years ago

Solve the system ... y=3x-8 and y=-9x+4

natita [175]

1] y - 3x = -8
[2] y + 9x = 4

-3x + y = -8 9x + y = 4

Solve equation [2] for the variable y

[2] y = -9x + 4

// Plug this in for variable y in equation [1]

[1] (-9x+4) - 3x = -8
[1] - 12x = -12
// Solve equation [1] for the variable x

[1] 12x = 12

[1] x = 1
// By now we know this much :

y = -9x+4
x = 1
// Use the x value to solve for y

y = -9(1)+4 = -5

{y,x} = {-5,1}

7 0

2 years ago

I need help on this one

mel-nik [20]

Answer: 4/9

Step-by-step explanation:

apply product rule to 2/3 2^2 / 3^2

7 0

3 years ago

What is the quotient of the following division problem?

Whitepunk [10]

Answer:

D. 10r7

Explaination:

9 goes into 97 10 times, and has a remainder of 7

7 0

3 years ago

An envelope contains three cards: a black card that is black on both sides, a white card that is white on both sides, and a mixe

Over [174]

Answer:

There is a 2/3 probability that the other side is also black.

Step-by-step explanation:

Here let B1: Event of picking a card that has a black side

B2: Event of picking a card that has BOTH black side.

Now, by the CONDITIONAL PROBABILITY:

$P(B_2/B_1 ) = \frac{P(B_1\cap B_2)}{P(B_1)}$

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.

⇒ P (B1 ∩ B2) = 1 /3

Also, Out if total 6 sides of cards, 3 are BLACK from one side.

⇒ P (B1 ) = 3 /6 = 1/2

Putting these values in the formula, we get:

$P(B_2/B_1 ) = \frac{P(B_1\cap B_2)}{P(B_1)} = \frac{1}{3} \times\frac{2}{1} = \frac{2}{3}$

⇒ P (B2 / B1) = 2/3

Hence, there is a 2/3 probability that the other side is also black.

5 0

3 years ago