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algol13
4 years ago
5

A flower bed is in the shape of a triangle, with a base of 11 feet and a height of 7 feet. What is the area of the flower bed?

Mathematics
2 answers:
Amanda [17]4 years ago
6 0

Answer:

38.5 square feet

Step-by-step explanation:

base x height then divide the answer by 2

Nikolay [14]4 years ago
5 0

Answer:

38.5 square feet

Step-by-step explanation:

the area of the triangle is (11x7)/2. That would be 77/2, which is 38.5.

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What is -9.25 as a faction
melamori03 [73]

Answer:

-37 / 4

Step-by-step explanation:

8 0
3 years ago
A line with a slope of 1/2 passes through (-5,-2). Write the equation of the line in standard form.
ch4aika [34]
5-4 //jzbbxbxbzbbsjd jsjdjcn ñandú
5 0
3 years ago
My brainy brother and sister added their ages together and got 15. When they multiplied their ages together, they got 54. How ol
Vinvika [58]

Given:

Sum of ages of brother and sister = 15

Product of their ages = 54

To find:

How old is the older one between the two of them?

Solution:

Let x be the age of brother and y be the age of sister.

Sum of ages of brother and sister = 15

x+y=15

x=15-y                ...(i)

Product of their ages = 54

xy=54

(15-y)y=54                [Using (i)]

15y-y^2=54

0=54-15y+y^2

Splitting the middle term, we get

54-15y+y^2=0

54-9y-6y+y^2=0

9(6-y)-y(6-y)=0

(6-y)(9-y)=0

Using zero product property, we get

(6-y)=0\text{ and }(9-y)=0

y=6\text{ and }y=9

If y=6, then using (i), we get

x=15-6

x=9

If y=9, then using (i), we get

x=15-9

x=6

Therefore, the age of older one is 9, the age of younger one is 6 and the difference between their ages is 3.

6 0
3 years ago
Convert please
dezoksy [38]
<h3>Answer:</h3>
  1. 3,8 kg
  2. 750 g
  3. 7,47 g
<h3>Step-by-step explanation:</h3><h3>3800 g => kg</h3>

(3800 ÷ 1000) kg

= 3,8 kg

<h3>¾ kg => g</h3>

(3 ÷ 4)kg × 1000

= 0.75 × 1000

= 750 g

<h3>7470 g => kg</h3>

(7470 ÷ 1000) kg

= 7,47 kg

4 0
3 years ago
F(x) = x² – 3x; Find f(-8)
Shtirlitz [24]
F(-8)=8^2-3(-8)
=64+24
=88

Hope this can help.
7 0
3 years ago
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