A line with a slope of 1/2 passes through (-5,-2). Write the equation of the line in standard form.

WILL GIVE ALOT OF POINTS HELP FAST One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant

den301095 [7]

Answer:

4.4

Step-by-step explanation:

16.8 was for 4 hour

divide 4 by 16.8

you get 4.2 per hour

so you need 1 hour

1 hour would be 4.2

temp would be -4.2 at 9pm

4 0

3 years ago

Read 2 more answers

3.2x + 7.9 + 8.2 + 6.7x Simplify the expressions. (not equations!) Please help ASAP.

Temka [501]

Answer:

9.9x + 16.1

Step-by-step explanation:

SImplify using like terms

Simplify:

3.2x + 7.9 + 8.2 + 6.7x
3.2x + 6.7x + 7.9 + 8.2
9.9x + 16.1

-Chetan K

4 0

2 years ago

Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The

ExtremeBDS [4]

Answer:

800 kph
600 kph

Step-by-step explanation:

Equation

Let s represent the speed of the faster plane. Then its travel time is ...

time = distance/speed = 3600/s

travel time for the slower plane is ...

time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

3600/(s -200) -3600/s = 1.5

Solution

Multiplying by (2/3)s(s -200), we get ...

2400(s) -2400(s -200) = s(s -200)

s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

(s -800)(s +600) = 0 . . . . . . . . . . . . . factor

The positive value of s that makes a factor zero is s = 800.

Conclusion

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

Check

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

6 0

2 years ago

Which shows the expression below simplified? 0.00028 ÷ (7 × 10-4)

Katyanochek1 [597]

$0.\underbrace{00028}_{\rightarrow5places}=28\times10^{-5}\\\\0.00028:(7\times10^{-4})=\dfrac{28\times10^{-5}}{7\times10^{-4}}=\dfrac{28}{7}\times\dfrac{10^{-5}}{10^{-4}}\\\\=4\times10^{-5-(-4)}=4\times10^{-5+4}=\huge\boxed{4\times10^{-1}}\leftarrow\boxed{b.}\\\\used\ \dfrac{a^n}{a^m}=a^{n-m}$

6 0

3 years ago

Find a polynomial of degree 3 with real coefficients and zeros of -3,-1, and 4, for which f(-2)=-24

Zanzabum

We want to find a polynomial

f(x) = a x³ + b x² + c x + d

such that the roots of f are x = -3, x = -1, and x = 4, and f(x) takes on a value of -24 when x = -2.

The factor theorem for polynomials tells us that we can factorize f(x) as

a x³ + b x² + c x + d = a (x + 3) (x + 1) (x - 4)

Expand the right side:

(x + 3) (x + 1) (x - 4) = x³ - 13x - 12

So we have

a x³ + b x² + c x + d = a x³ - 13a x - 12a

In order for both sides to be equal, the coefficients of both polynomials on terms of the same degree must be equal. This means

a = a (of course)

b = 0 (there is no x² term on the right)

c = -13a

d = -12a

We also have that f (-2) = -24, which means

f (-2) = a (-2 + 3) (-2 + 1) (-2 - 4)

-24 = 6a

a = -4

which in turn tells us that c = 52 and d = 48.

So we found

f(x) = -4x³ + 52x + 48

4 0

2 years ago