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lord [1]
3 years ago
9

Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale. if she bought 22 frames

for $239, find how many of each type she bought.
Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

small frames ($8): s

large frames ($15): L


Cost:        8s + 15L = 239   ⇒ 1(8s + 15L = 239)   ⇒    8s + 15L = 239  

Quantity:   s  +   L   = 22   ⇒  -8( s  +   L   = 22)   ⇒  <u> -8s   -8 L  = -176 </u>

                                                                                               7L  = 63

                                                                                                  L = 9

Quantity:   s + L = 22 ⇒   s + (9) = 22   ⇒   s = 13

Answer: 13 small frames, 9 Large frames

Alex17521 [72]3 years ago
7 0

Answer:

9 large frames and 13 small frames

Step-by-step explanation:

Then number of each type can be found simultaneously by interpreting the given statements into equations. As such, if the number of the large frames and small frames purchased are a and b respectively. if she bought 22 frames then,

a + b = 22

Furthermore, if Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale for $239 then

15a + 8b = 239

solving both simultaneously,

b = 22 - a

15a + 8(22 - a) = 239

15a -8a + 176 = 239

7a = 239 - 176

7a = 63

a = 9

b = 22 - 9

= 13

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3 years ago
Read 2 more answers
Could you please explain it?
Troyanec [42]
Hello,
there are some words that I could not read. But:
I support evements are independants.
p(s)=0.2
p(l)=1-0.2=0.8 l=lose

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3 years ago
If PN=29cm and MN=13 , then PM=?
HACTEHA [7]

*see attachment for the figure referred to

Answer/Step-by-step explanation:

1. PN = 29

MN = 13

PM = ?

PN = PM + MN (Segment addition postulate)

PN - MN = PM (subtract MN from each side)

29 - 13 = PM (substitute)

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PM = 16 cm

2. PN = 34, MN = 19, PM = ?

PN = PM + MN (sediment addition postulate)

PN - MN = PM (subtract MN from each side)

34 - 19 = PM (substitute)

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3. PM = 19, MN = 23, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 19 + 23 (substitute)

PN = 42 cm

4. MN = 82, PN = 105, PM = ?

PN = PM + MN (segment addition postulate)

PN - MN = PM (subtract MN from each side)

105 - 82 = PM (substitute)

23 = PM

PM = 23 cm

5. PM = 100, MN = 100, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 100 + 100 (substitute)

PN = 200 cm

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