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lord [1]
3 years ago
9

Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale. if she bought 22 frames

for $239, find how many of each type she bought.
Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

small frames ($8): s

large frames ($15): L


Cost:        8s + 15L = 239   ⇒ 1(8s + 15L = 239)   ⇒    8s + 15L = 239  

Quantity:   s  +   L   = 22   ⇒  -8( s  +   L   = 22)   ⇒  <u> -8s   -8 L  = -176 </u>

                                                                                               7L  = 63

                                                                                                  L = 9

Quantity:   s + L = 22 ⇒   s + (9) = 22   ⇒   s = 13

Answer: 13 small frames, 9 Large frames

Alex17521 [72]3 years ago
7 0

Answer:

9 large frames and 13 small frames

Step-by-step explanation:

Then number of each type can be found simultaneously by interpreting the given statements into equations. As such, if the number of the large frames and small frames purchased are a and b respectively. if she bought 22 frames then,

a + b = 22

Furthermore, if Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale for $239 then

15a + 8b = 239

solving both simultaneously,

b = 22 - a

15a + 8(22 - a) = 239

15a -8a + 176 = 239

7a = 239 - 176

7a = 63

a = 9

b = 22 - 9

= 13

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Given Information:

Number of endangered mammal species = 59

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Required Information:

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Answer:

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Step-by-step explanation:

We want to randomly select one animal and find out the probability of either a mammal or a fish.

The total number of endangered species of animals is given by

Total animals = mammal species + bird species + fish species

Total animals = 59 + 75 + 68  = 202

The probability of selecting a endangered mammal is

P(mammal) = no. of endangered mammal/total no. of endangered animals

P(mammal) = 59/202

The probability of selecting a endangered fish is

P(fish) = no. of endangered fish/total no. of endangered animals

P(fish) = 68/202

Finally, the probability of selecting either a mammal or a fish is

P(mammal or fish) = 59/202 + 68/202

P(mammal or fish) = 127/202

P(mammal or fish) = 0.6287

P(mammal or fish) = 62.87%

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3 years ago
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