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3 years ago

What is the answer to -.3y=7.53

2 answers:

8 0

Well, I won't give you the direct answer, but I can give you clues to lead you to the answer:

1. divide both sides of the equation by -0.3
2. use a calculator of do the division by hand
3. this should cancel out the -.3 next to the y variable
4. essentially, 7.53/-0.3 is your answer

Hope that helps!

fiasKO [112]3 years ago

3 0

Y = - 25.1

I hope this helps.

I hope you pass! :D

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Evaluate each function.<br> 1) f(x) = x2 + 4x; Find f(-7)

katrin [286]

Answer:

The answer is -77

Step-by-step explanation:

Ok, so assuming by x2 you mean x squared, I will solve this. So basically when you have a function, f(-7) would mean that you would have to replace all the x's in the equation with -7. So let's write that out. that would be f(-7) = -7^2 + (-7*4). So now according to PEMDAS, you would solve the exponent first, and -7^2 is equal to -49, because when you solve it you would do -(7^2), which is -(49), which is then -49. So now you have f(-7)= -49+ (4*-7). Solving for (4*-7), you get -28. This leaves you with -49 + (-28), which is -49 - 28. Simplifying that, you get the answer, which is -77.

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3 years ago

Click on a factor pair of 32.

jasenka [17]

Answer:

1, 2, 4, 8, 16, 32

Step-by-step explanation:

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3 years ago

Find m<LMN if m<LMT=23 degree and m<TMN=144 degree

rodikova [14]

Answer:

∠LMN = 167°

Step-by-step explanation:

∠LMT = 23°

∠TMN = 144°

∠LMN = ∠LMT + ∠TMN

∠LMN = 23° + 144°

∠LMN = 167°

5 0

3 years ago

What are the coordinates of the terminal point for 8 = 330°?

galben [10]

Answer:

Step-by-step explanation:

If you plot this angle in the coordinate plane, you will find yourself in the fourth quadrant with a referencew angle of 30. Constructing the triangle from that reference angle and using the Pythagorean triple for a 30-60-90 triangle, you get that the side adjacent to the reference angle is √3, the side opposite the reference angle is a -1, and the hypotenuse (which is NEVER negative!) is 2. The x and y coordinates of the terminal point result from the cos (related to the x coordinate) and the sin (related to the y coordinate). The cos of 30:

$cos(30)=\frac{\sqrt{3} }{2}$ and the sin of 30:

$sin(30)=-\frac{1}{2}$ so the coordinates of the terminal point on that angle are

$(\frac{\sqrt{3} }{2},-\frac{1}{2})$

You could also just go to your unit circle, find the angle 330 and look at the coordiantes they give you there for (cos, sin). But I'm a high school math teacher so I wanted you to know how to find this outside of the unti circle. Cuz what if you lost it!?

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3 years ago

Find a function f such that f '(x) = 5x3 and the line 40x + y = 0 is tangent to the graph of f.

Alex17521 [72]

The function that is a tangent to the graph of f is $f(x) = (5/4)x^4+60$

<h3>What is the concept of integral?</h3>

The definite integral can be interpreted as the resulting area of a region. In addition, it is a value in its result, that is, it does not depend on the variable x, which can be exchanged for any other variable without changing the value of the integral.

Knowing that :

40x + y = 0 is tangent of f(x)
slope of the line = -40

therefore, f'(x)|x=a = -40, so only look for a we have:

$5a^3 = -40\\a^3 = -8\\a = -2$

if, x = -2, then y = 80 (since, 40x + y = 0), therefore, f(x) passes through (-2,80), so in the equation:

$f'(x) = 5x^3\\f(x) = (5/4)x^4 + c\\80 = (5/4)(-2)^4 + c\\c = 60$

Therefore,

$f(x) = (5/4)x^4+60$

See more about tangent at brainly.com/question/401236

#SPJ1

4 0

2 years ago