Answer:
Step-by-step explanation:
24 p=72
Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
It's kind of not C.
Solve this proportion for 'x':
3/50 = x/2400
Hint: Cross-multiply the proportion, then do what you need to do.
What she ate is
(13/4)×(5/7)
65/28 pounfs of candy
Answer:
The orange sample
Step-by-step explanation:
The higher the interquartile range the bigger the variance as it the difference between the 0.25 and 0.75 quantiles which basically means if the difference between the 25 percent and 75 percent is higher then there is more variety as they are further away
Would be amazing if you marked brainliest and feel free to comment any follow up questions :)
