Answer:
Carbon Dioxide is an Infrared Radiation Absorber. The (CO2) molecules also emits the absorbed infrared (IR) radiation energy. The photon energy from the infrared radiation causes the CO2 molecule to vibrate. Only some of its vibrational modes absorb infrared radiation
Explanation:
Its linear structure is considered when working with the formula to calculate the number of molecular vibrational modes. It has 3n - 4 vibrational modes, where n is the number of atoms in a compound of CO2
With 3 atoms, CO2 has
3n−5=4 types or patterns of vibration
1. The symmetric stretch
2. The asymmetric stretch
3. The bend
The symmetric stretch vibrational mode is ir-inactive.
The asymmetric stretch is ir-active as it results in changes in dipole moment
The bend is ir-active as well as it results in a change in dipole moment too.
Answer:
the result is C and D. those are the ansers
Answer:
4.07
Explanation:
There is some info missing. I think this is the original question.
<em>A solution is prepared at 25 °C that is initially 0.057 M in nitrous acid (HNO₂), a weak acid with Ka = 4.5 × 10⁻⁴, and 0.30 M in sodium nitrite (NaNO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.</em>
<em />
Nitrous acid is a weak acid and nitrite (coming from sodium nitrite) is its conjugate base. Together, the form a buffer system. We can calculate its pH using the Henderson-Hasselbach equation.
pH = pKa + log [base]/[acid]
pH = -log 4.5 × 10⁻⁴ + log 0.30/0.057
pH = 4.07
Answer: Option (d) is the correct answer.
Explanation:
The given equations as as follows.
(slow)
Therefore, overall reaction equation will be as follows.
So, cancelling the spectator ions then the equation will be as follows.
As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.
Rate law = ![k[H_{2}O_{2}][I^{-}]](https://tex.z-dn.net/?f=k%5BH_%7B2%7DO_%7B2%7D%5D%5BI%5E%7B-%7D%5D)
Hence, the reaction is first order with respect to ![[I^{-}]](https://tex.z-dn.net/?f=%5BI%5E%7B-%7D%5D)
and it is also first order reaction with respect to ![[H_{2}O_{2}]](https://tex.z-dn.net/?f=%5BH_%7B2%7DO_%7B2%7D%5D)
.
Also, acts as a catalyst in the reaction.
Thus, we can conclude that the incorrect statement is 
is a catalyst.
