Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line
Answer: D. test tubes, thermometers, etc
I think this is the correct answer. Sorry if it is not.
Explanation:
Answer:
The number of energy levels will increase.
Explanation:
As they are all Noble Gases, they are all in the same family. However, as you go further down the list of Noble Gases, the period number increases. The period number shows the number of energy levels. Hence, an increase in energy levels.
Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.
<h3>Percent yield</h3>
The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
<h3>Percent yield in this case</h3>
In this case, you know:
- actual yield= 1.22 mol
- theorical yield= 1.60 mol
Replacing in the definition of percent yields:
Solving:
<u><em>percent yield= 76.25%</em></u>
Finally, the percent yield for the reaction is 76.25%.
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volume of H₂O = 7.2 L
Explanation:
The combustion reaction of methane (CH₄):
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Now we calculate the number of moles of methane using the following formula:
number of moles = volume / 22.4 (L/mole)
number of moles of CH₄ = 3.6 / 22.4
number of moles of CH₄ = 0.16 moles
Taking in account the chemical reaction, we devise the following reasoning:
if 1 mole of CH₄ produce 2 moles of H₂O
then 0.16 moles of CH₄ produce X moles of H₂O
X = (0.16 × 2) / 1 = 0.32 moles of H₂O
And now we can calculate the volume of water (H₂O) produced by the reaction:
number of moles = volume / 22.4 (L/mole)
volume = number of moles × 22.4 (L/mole)
volume of H₂O = 0.32 × 22.4
volume of H₂O = 7.2 L
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combustion reaction
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