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Schach [20]
4 years ago
12

Describe a method for making pure crystals of magnesium chloride from magnesium and dilute hydrochloric acid. In your method, yo

u should name the apparatus you will use. (6 mark question)
Chemistry
1 answer:
Musya8 [376]4 years ago
8 0

Answer:

Check Explanation.

Explanation:

Magnesium and dilute hydrochloric acid react with each other to produce Magnesium Chloride and liberate hydrogen gas according to the reaction

Mg (s) + 2HCl (aq) → MgCl₂ (aq) + H₂ (g)

The procedure to obtain pure magnesium chloride from the reaction is as thus

Step 1: Reaction

- Leave the dilute hydrochloric acid in a beaker.

- Add Magnesium slowly until it is in excess or until no more gas seem to be getting liberated.

Step 2: Filtration

- Filter with filter paper and funnel.

- Filter off the excess magnesium as magnesium chloride will be in aqueous form (liquid) and will come out with the filtrate. The residue is the excess magnesium.

Step 3: Crystallization to obtain solid crystals from the filtrate.

- Pour filtrate solution into evaporating dish/basin

- Provide heat using Bunsen burner

- Pour solution into an evaporating basin and heat over a water bath

- Stop heating when crystals start to form

allow water to evaporate until pure crystals remain.

- Dry crystals using absorbent paper or warm oven.

Precautions

- Use personal protective equipment such as gloves, a lab coat and wear eye protection, especially when heating.

- Avoid inhaling unnecessary gases during the whole process.

Hope this Helps!!!

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Answer:

\boxed{\text{6.00 mol/L}}

Explanation:

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2HCl + Ca(OH)₂ ⟶ CaCl₂ + 2H₂O  

(b) Moles of Ca(OH)₂

\text{Moles of base} = \text{2.00L} \times \dfrac{\text{1.50 mol}}{\text{1 L}} = \text{3.000 mol base}

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\text{Moles of HCl} = \text{3.000 mol base} \times \dfrac{ \text{2 mol HCl}}{\text{1 mol base}} = \text{6.000 mol HCl}

(d) Molar concentration of HCl

\text{Molar concentration} = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{ n }{ V}\\\\c= \dfrac{ \text{6.000 mol}}{ \text{1.000 L}} = \text{6.00 mol/L}

The molar concentration of the HCl was \boxed{\textbf{6.00 mol/L}}

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Answer:

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