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Tamiku [17]
3 years ago
11

Is 3 : 4 = 6 : 8 proportional ?

Mathematics
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

yes it's proportional

Step-by-step explanation:

3/4=6/8

3(8)=6(4)

24=24

belka [17]3 years ago
8 0

Answer:

Step-by-step explanation:

3:4=6:8

3/4=6/8

Cross multiply

3*8=4*6

24=24

Yes they are proportional

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How do you know the number of part to divide a number line from 0 to 1 into when comparing fractions
Katyanochek1 [597]
To compare fractions you need a common denominator, then you can make a comparison.  You would divide the number line between 0 and 1 (or any 2 whole numbers on the number line) based on that common denominator.  For example... if you were trying to compare 3/4 and 2/8, you would find the common denominator (in this case 8) and convert the fractions...

3/4 = 6/8
2/8 stays as 2/8

Now you would go to the number line between 0 and 1 and divide it into 8 equal pieces.  3/4 would go over the 6th division and 2/8 would go over the second division. 

That would give you a good visual that 2/8 < 3/4

[        /        /        /        /        /        /        /        ]

0              2/8                               3/4               1
4 0
4 years ago
Let F=(2x,2y,2x+2z)F=(2x,2y,2x+2z). Use Stokes' theorem to evaluate the integral of FF around the curve consisting of the straig
Brilliant_brown [7]

Stokes' theorem equates the line integral of \vec F along the curve to the surface integral of the curl of \vec F over any surface with the given curve as its boundary. The simplest such surface is the triangle with vertices (1,0,1), (0,1,0), and (0,0,1).

Parameterize this triangle (call it T) by

\vec s(u,v)=(1-v)((1-u)(1,0,1)+u(0,1,0))+v(0,0,1)

\vec s(u,v)=((1-u)(1-v),u(1-v),1-u+uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to T to be

\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=(0,1-v,1-v)

Divide this vector by its norm to get the unit normal vector. Note that this assumes a "positive" orientation, so that the boundary of T is traversed in the counterclockwise direction when viewed from above.

Compute the curl of \vec F:

\vec F=(2x,2y,2x+2z)\implies\mathrm{curl}\vec F=(0,-2,0)

Then by Stokes' theorem,

\displaystyle\int_{\partial T}\vec F\cdot\mathrm d\vec r=\iint_T\mathrm{curl}\vec F\cdot\mathrm d\vec S

where

\mathrm d\vec S=\dfrac{\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}}{\left\|\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}\right\|}\,\mathrm dS

\mathrm d\vec S=\dfrac{\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}}{\left\|\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}\right\|}\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\mathrm d\vec S=\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv

The integral thus reduces to

\displaystyle\int_0^1\int_0^1(0,-2,0)\cdot(0,1-v,1-v)\,\mathrm du\,\mathrm dv=\int_0^12(v-1)\,\mathrm dv=\boxed{-1}

3 0
3 years ago
Solve for:-9a = 27 <br> please someone help!!!
myrzilka [38]

Answer:

a = -3

:)))))))))))))))

6 0
3 years ago
What is the distance between points (8,11) and (8,−2) on a coordinate plane?
tatuchka [14]
Answer: 13 units is the distance between the points.
4 0
3 years ago
1.) An architect is designing a house with steps to
ExtremeBDS [4]

Answer:

  About 3.36 feet or about 40.3 inches

Step-by-step explanation:

The tangent ratio tells you ...

  Tan = Opposite/Adjacent

In this geometry, we want ...

  tan(50°) = (4 ft)/(distance)

Solving for distance gives ...

  distance = (4 ft)/tan(50°) ≈ 3.3564 ft ≈ 40.28 in

The steps need to start about 3.36 feet, or about 40.3 inches, out from the house.

4 0
3 years ago
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