How to estimate 19 divided 1425

Which of the following options results in a graph that shows exponential growth? f(x) = 0.4(3)x f(x) = 3(0.5)x f(x) = 0.8(0.9)x

Leto [7]

It's important that you use the correct symbol to indicate exponentiation.

<span>f(x) = 0.4(3)x f(x) = 3(0.5)x f(x) = 0.8(0.9)x f(x) = 0.9(5)−x should be written as:

</span><span>f(x) = 0.4(3)^x f(x) = 3(0.5)^x f(x) = 0.8(0.9)^x f(x) = 0.9(5)−x.

Please double-check that last problem, as I am unsure of whether you meant 0.9^5 or (0.9)(5).

f(x) = 0.4(3)^x is definitely an exponential function.

Please try again. Do those problems that you can do an ask questions about the others.

</span>

4 0

4 years ago

Read 2 more answers

2 ( 4 x + 4 ) + 6 ( 2 x + 6 ) + 4 = 20 x + 48 solving for x

Alisiya [41]

Answer:

infinitely many solutions

Step-by-step explanation:

8x+8+12x+36+4=20x+48

20x + 48 = 20x + 48

0= 0

3 0

3 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

4 years ago

Can someone help me with this?

Mandarinka [93]

Answer:

Step-by-step explanation:

Area of rectangle = length * width

= (x + 4) (5x)

= x *5x + 4 *5x

= 5x² + 20x

Perimeter of rectangle = 2*(length + width)

= 2*(x + 4 + 5x)

= 2*(6x + 4)

= 2*6x + 2 *4

= 12x + 8

4 0

3 years ago

The angles in a triangle are in the ratio 2 : 3:7.

Mademuasel [1]

Answer:

30°, 45° and 105°

Step-by-step explanation:

2 + 3 + 7 = 12 parts

180/12 = 15 degrees each part

First angle (2 parts)

2(15) = 30°

Second angle (3 parts)

3(15) = 45°

Third angle (7 parts)

7(15) = 105°

Hope this helps

3 0

1 year ago