P = 10% = 0.1
q = 1 - 0.1 = 0.9
P(at least one defective calculator) = P(1) + P(2) + P(3) + P(4) = 1 - P(0)
The brobability of a binomial distribution is given by
where: n = 4
Therefore,
P(at least one defective calculator) = 1 - 0.6561 = 0.3439
The other endpoint would have to be (-5,2), going off the definition of a midpoint. Since 3 is for units to the right of -1, that would mean that the other end point would have to be 4 units to the left, which is -5.
<span>1.You should set up the long division.
</span>
2 <span>Calculate 43 ÷ 7, which is 6 with a remainder of 1.
</span>
3 <span>Bring down 1, so that 11 is large enough to be divided by 7.
</span>
4 <span>Calculate 11 ÷ 7, which is 1 with a remainder of 4.
</span>
5 <span>Bring down 8, so that 48 is large enough to be divided by 7.
</span>
6 <span>Calculate 48 ÷ 7, which is 6 with a remainder of 6.
</span>
7 <span>Therefore, 4318 ÷ 7 = 616 with a remainder of 6.
</span><span>
616 with</span> a remainder of 6 or 616.8571
I believe the answer would be 4ab^2
A perfect square is a number that can be expressed as the product of two equal integers.
The only way to accurately calculate if a number is a perfect square is to find the factors. Before we go through the trouble of finding the factors, there is a quick trick you can use to help determine if you need even need to do the extra work.
