From Sweatcoin, London to the residence of Santa Claus is about 4,280 km away.
<h3>Where is the Santa Clause's residence?
</h3>
The residence of Santa Clause is popularly known as the North Pole.
According to the above, we have to roughly calculate the distance from Sweatcoin in London to the North Pole. This distance is equivalent to about 4,280 km
Learn more about London in: brainly.com/question/7416097
<span>Answer:
17576=pir^2h
the amount of material M=2pir^2 +2pirh
M=2pir^2+2pir(17576/pir^2)
DrM= 4pir- 35152/r^2
DrM=0
0=4pir- 35152/r^2
r=(13*2^(2/3))/pi^(1/3)
17576=pi((13*2^(2/3))/pi^(1/3))^2)h
17576/(pi((13*2^(2/3))/pi^(1/3))^2))=h
r=14.0901
h=28.1801
M=3742.21 cm^2</span>
Let x be the number of hours it will take for Atu and Brek to meet and cover the total distance of 420. The distance covered is the product of the speed and time. Thus,
56x + 49x = 420
105x = 420
The value of x from the derived equation is equal to 4 hours.
One hour less than the number of hours calculated above is 3 hours. The distances covered are calculated below.
Atu = (56 mph)(3 hours) = 168 miles
Brek = (49 mph)(3 hours) = 147 miles
The total distance covered is equal to 315 miles.
Subtracting this distance from the given total distance.
difference = 420 miles - 315 miles = 105 miles
<em>ANSWER: 105 miles</em>
Answer: 1 1/4 cups of vegetable oil left over.
Step-by-step explanation: 1/2 cup for Cakepops and 1.5 times (3/4 cup) for cup cakes.
2 1/2 - 1/2 - 3/4
Supposing you know about the derivative, notice that
![\displaystyle\lim_{h\to0}\frac{\ln(x+h)-\ln x}h=\dfrac{\mathrm d(\ln x)}{\mathrm dx}=\dfrac1x](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bh%5Cto0%7D%5Cfrac%7B%5Cln%28x%2Bh%29-%5Cln%20x%7Dh%3D%5Cdfrac%7B%5Cmathrm%20d%28%5Cln%20x%29%7D%7B%5Cmathrm%20dx%7D%3D%5Cdfrac1x)
so that when
, the limit is equal to
and the answer is A.