The rate law for the reaction NH4(aq)+ + NO2(aq)- → H2O(l) + NO2(g) is rate = k [NH4+][NO2-], and the value of k is 2.7*10-4 M-1

Question

victus00 [196]

3 years ago

8

The rate law for the reaction NH4(aq)+ + NO2(aq)- → H2O(l) + NO2(g) is rate = k [NH4+][NO2-], and the value of k is 2.7*10-4 M-1

s-1. What is the rate of reaction when [NH4+] = 0.050 M and [NO2-] = 0.25 M?

Chemistry

2 answers:

dybincka [34] · Answer 1 · 2022-05-10T06:08:02+03:00

dybincka [34]3 years ago

8 0

We are given the rate law, so we can substitute the given values for the rate constant and the concentrations of the reactants to solve for the rate of reaction. Since rate = k [NH4+][NO2-]:
rate = (2.7 x 10^-4 / M-s)(0.050 M)(0.25 M) = 3.375 x 10^-6 M/s

saw5 [17] · Answer 2 · 2022-05-10T08:19:03+03:00

saw5 [17]3 years ago

8 0

3.4*10^6 Ms-1 You have successfully calculated the rate at the given conditions.