Correct Question: what is the oxidizing agent in the reaction.
2MnO4–(aq) +10Cl–(aq) + 16H+(aq) --------> 5Cl2(g) + 2Mn2+(aq) +8H2O(l)
Answer: MnO4-is the oxidizing agent
Explanation:
In the reaction 2MnO4–(aq) +10Cl–(aq) + 16H+(aq) --------> 5Cl2(g) + 2Mn2+(aq) +8H2O(l)
Oxidizing agent oxidizes other molecules while the themselves get reduced.
oxidizing agents give away Oxygen to other compounds.
MnO4-is the oxidizing agent because
On the reactants side
Oxidation number of Mn in 2MnO4- is +7
Oxidation number of Cl- is -1
On the products side
Oxidation number of Mn is +2
While oxidation number of Cl is zero
Therefore the oxidizing agent is 2MnO4 because is oxidizes Chlorine from -1 to 0 while itself got reduced from oxidation state of +7 to +2
Answer:Ocean breezes keep coastal Galveston cooler than Del Rio, which is inland and exposed to southerly winds.
Explanation: inwards has winds and outwards doesn’t have winds just the coast.
Brass is an alloy, or a combination of two (or more) metals.
Answer:
Explanation:
There are few simple rules in organic chemistry which a person must learn.
1. In predicting a structure from ozonolysis, number of oxygen present in products must be counted. In this particular example, there are 2+3+1 = 6 oxygen atoms are present in three molecules. This means that there should be at least three confirmed double bonds must be present in the molecule of Dictyopterene.
2. There are in total of 3+5+3 = 11 carbon atoms present, making 2^11 = 2048 possible structures for this particular structure. But since there are three double bonds present, this will reduce the number of possible structures as well.
3. Questions also says that when fully hydrogenated, the molecule generates Butylcycloheptane. That means that our base molecule is Butylcycloheptane and this molecule contains at least three double bonds.
So, first we draw the molecule of butylcycloheptane. After this, we think of were double bonds could be present. We do have the products. Let's make their structures first. I have also mentioned the possible breakup where the ozonolysis has occured by color code. You can see them in the reference image attached.
Part 1 out of 2: There is only one chiral carbon present in the molecule and have two possible isomers. Cis and Trans. Only one stereogenic carbon is present, that's why two possible isomers. Image attached.