The molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
<h3>HOW TO CALCULATE MOLAR CONCENTRATION:</h3>
- The molar concentration of a solution can be calculated by dividing the number of moles by its volume.
- According to this question, there are 469 grams of C6H12O6 in 82 milliliters of water.
The number of moles = 469g ÷ 180.156g/mol = 2.6mol
Volume of water in litres = 82/1000 = 0.082L
Concentration of solution = 2.6mol ÷ 0.082L = 31.71M
Therefore, the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.
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The new volume when pressure increases to 2,030 kPa is 0.8L
BOYLE'S LAW:
The new volume of a gas can be calculated using Boyle's law equation:
P1V1 = P2V2
Where;
- P1 = initial pressure (kPa)
- P2 = final pressure (kPa)
- V1 = initial volume (L)
- V2 = final volume (L)
According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:
406 × 4 = 2030 × V2
1624 = 2030V2
V2 = 1624 ÷ 2030
V2 = 0.8L
Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.
Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults
<u>Answer:</u> The correct option is D) 
<u>Explanation:</u>
The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction. It occurs when oxidation number of a species increases.
A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction. It occurs when oxidation number of a species decreases.
For the given chemical reaction:

<u>On the reactant side:</u>
Oxidation number of Zn = 0
Oxidation number of Ag = +1
<u>On the product side:</u>
Oxidation number of Zn = +2
Oxidation number of Ag = 0
As the oxidation number of Ag is decreasing from +1 to 0. Thus,
is getting reduced.
Hence, the correct option is D) 
We calculate the entropy of an ideal gas follows:
<span>For an isothermal compression, change in internal energy is equal to zero.</span>
<span>Thus, the heat added to the gas is equal to the work done on the gas which is given as 1750 J.</span>
<span>Entropy would be 1750/301 = 5.81 J/K </span>