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Licemer1 [7]
2 years ago
10

How can you use factoring to solve quadratic equations in standard form ?

Mathematics
1 answer:
Sergio039 [100]2 years ago
8 0

Answer:

bro you need to give more

Step-by-step explanation:

You might be interested in
Sarah and Gavyn win some money and share it in the ratio 5:3. Sarah gets £26 more than Gavyn. How much did Gavyn get?
maks197457 [2]

Answer:

£39

Step-by-step explanation:

Let Gavyn's share = x

Since, Sarah gets £26 more than Gavyn.

Sarah's Share = x+26

Equating the Ratio of their Shares and the actual sum received

x+26 : x = 5:3

Converting to Fractions

\dfrac{x+26}{x}=\dfrac{5}{3}

Cross multiply

5x=3(x+26)

5x=3x+78

5x-3x=78

2x=78

Divide both sides by 2

x=39

Therefore: Gavyn's share x = £39

4 0
3 years ago
The area of a rectangle is 14 m2 , and the length of the rectangle is 3 m less than double the width. find the dimensions of the
muminat
Width =3.5, length = 4

Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl

Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w

0 = 2w^2 - 3w - 14

which factors into
(2w - 7) (w + 2)

Solving for w
2w - 7 = 0
2w = 7
w = 3.5

w+2 = 0
w = -2

So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5

Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14

So the width is 3.5 and the length is 4.

3 0
3 years ago
Need help... on this one plsss help
Scrat [10]

Answer:

A

Step-by-step explanation:

Tiffany should have multiplied by 0.5 in step 1, not divided.

5 0
3 years ago
Read 2 more answers
The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims
kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is \mu=600, we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it \sigma) is

\sigma=48

Next they draw a random sample of n=70 students, and they got a mean score (denoted by \bar x) of \bar x=613

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis H_0:\bar x \geq \mu

- The alternative would be then the opposite H_0:\bar x < \mu

The test statistic for this type of test takes the form

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\

<h3>since 2.266>1.645 we  can reject the null hypothesis.</h3>
6 0
3 years ago
Read 2 more answers
Line segment MN has endpoints M(4,-5) and N(-3,1). Find MN.
pshichka [43]
9.2195444572928873100022742817628. or square root of 85

8 0
3 years ago
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