Question

Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semester. What is the probability that less than 1 student will have his automobile stolen during the current semester

Answer 1

Answer:

$P(x>1)=0.9927$

Step-by-step explanation:

From the question we are told that:

Mean $\=x =7$

Generally the Poisson equation for \=x is mathematically given by

$P(x>1)=1-P(x \leq 1)$

Therefor

$P(x>1)=1-(\frac{e^{-7}*7^0}{0!}+{\frac{e^{-7}*7^1}{1!})$

$P(x>1)=1-(9.1*10^{-4}+6.3*10^{-3})$

$P(x>1)=1-(7.3*10^{-3}$

$P(x>1)=0.9927$