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zepelin [54]
3 years ago
12

Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semest

er. What is the probability that less than 1 student will have his automobile stolen during the current semester
Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:

P(x>1)=0.9927

Step-by-step explanation:

From the question we are told that:

Mean \=x =7

Generally the Poisson equation for \=x is mathematically given by

P(x>1)=1-P(x \leq 1)

Therefor

P(x>1)=1-(\frac{e^{-7}*7^0}{0!}+{\frac{e^{-7}*7^1}{1!})

P(x>1)=1-(9.1*10^{-4}+6.3*10^{-3})

P(x>1)=1-(7.3*10^{-3}

P(x>1)=0.9927

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Help please if you can thanks
8_murik_8 [283]

Answer:

A. 8

Step-by-step explanation:

1kg=2.2

18.5 lbs= 8kg

5 0
3 years ago
Read 2 more answers
The value of a new car decreases by about 15% in the first year. How much will a car be worth after one year if its initial valu
Masja [62]

Answer:

(a)

$850.

(b)

$4250.

(c)

$4267.

Step-by-step explanation:

It is given that the value of a new car decreases by about 15% in the first year.

(a)

Now we are asked to find the cost of a car after one year; if we are given the initial value of car=$1000.

As the rate decreases by 15%.

that means we have to pay (100-15)% of the initial amount.

i.e. we have to pay 85% of the initial amount.

Hence the amount one has to pay= 85% of 1000.

which is equal to =85%×1000

⇒   =\dfrac{85}{100}\times 1000\\\\=85\times 10\\\\=850

Hence, the amount of car after one year when initaial amount is $1000 is:

$850.

(b)

if initial amount=$ 5000

then amount one has to pay after one year:

85\%\times 5000\\ \\=\dfrac{85}{100}\times 5000\\\\=4250

Hence, the amount of car after one year when initaial amount is $5000 is:

$4250.

(c)

if initial amount=$ 5020

then amount one has to pay after one year:

85\%\times 5020\\ \\=\dfrac{85}{100}\times 5020\\\\=4267

Hence, the amount of car after one year when initaial amount is $5020 is:

$4267.

7 0
3 years ago
Complete the table of values for y= x^2-2x-3
Levart [38]

Answer:

x=3,y=0

x=-1,y=0

Step-by-step explanation:

We will have to factorise to get the value of x before solving for y

Let's solve

y=x^2-2x-3

To factorise x

x^2-3x+x-3

x(x-3)+1(x-3)

(x-3)+(x+1)

x-3=0

x=3

x+1=0

x=-1

Let's substitute the value of value to get the value for y

y=x^2-2x-3

When x is 3

y=3^2-2(3)-3

y=9-6-3

y=0

When x is-1

y=(-1)^2-2(-1)-3

y=1+2-3

y=0

Therefore when x is 3,y is 0

When x is -1,y is 0

3 0
4 years ago
Read 2 more answers
3. The width of a rectangle is 3x – 7. The length of the rectangle is 4x +5.
garri49 [273]

Answer:

D. 14x - 4

Step-by-step explanation:

P = 2(L + W)

P = 2(4x + 5 + 3x - 7)

P = 2(7x - 2)

P = 14x - 4

3 0
3 years ago
11)-2=2+v/4 what’s the answer to this
Tatiana [17]
(4) -2 = 2 + v/4 (4)
-8 = 2 + v
-2 -2
V = -10

8 0
3 years ago
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