A triangle has a 90 degree angle and two sides that measure 5cm in length. Read the statements

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0

3 years ago

Please help with this math question

nika2105 [10]

263.27 m^2

rectangle : 15 x 10 = 150 m^2
the half circle at the top has a diameter of 6m. therefore, it’s radius is 3m. if it is cut in half, the part removed from the triangle height is 3m. therefore, the height of the triangle is 35 -15 = 20; 20 - 3 = 17. the height of the triangle is 17. the triangle area formula is a = 1/2(bh).
a = 1/2 (10)(17)
a = 1/2 (170)
a = 85 m^2
the circle would be a = πr^2 but divided by 2 bc it’s a half circle
a = π(3)^2
a = π9
a = 28.27 m^2
150 + 85 + 28.27 = 263.27 m^2

3 0

3 years ago

I’m confused on this one

ad-work [718]

The question is "What is the scale of the model to the actual statue"

That means you must put 2/15.

2 being the model

15 being the actual statue

Take that fraction and equal is to 1/x.

Multiply 15 to 1 and 2 to x.

In the end, to solve, you divide 15 by 2x.

The answer is X=7.5

1 : 7.5

7 0

3 years ago

How to solve rational equations

VashaNatasha [74]

Answer:

A rational number is a number that can be represented a/b where a and b are integers and b is not equal to 0.

Find the common denominator.

Multiply everything by the common denominator.

Simplify.

Check the answer(s) to make sure there isn't an extraneous solution.

4 0

3 years ago

There are 36 students in Mrs.Keatons's sixth grade class. If 5/12 of her students are girls, how many girls in the class?

murzikaleks [220]

There are 15 girls because 12 x 3 = 36 and 5 x 3 = 15

6 0

3 years ago