Answer:
Step-by-step explanation:
x 1 = π , x 2 = 3 π/ 2
y 1 = - 1, y 2 = 2
The Rate of change = ( y 2 - y 1) / ( x 2 - x 1 )=
= [2 -( -1 )] : ( 3 π /2 - π ) = 3 : π/2 = 6 / π <em>≈ 1.91 </em>
Answer: a=-4
Step-by-step explanation:
Answer:
P(B and V)=10%
Step-by-step explanation:To solve this poroblema we use the formula of combinations:
C(n,r)=(nr)=n!(r!(n−r)!)
Where n is the number of objects that can be chosen and you choose r from them.
There are 5 colors of shirts.
The number of shirts that can be made by combining 2 of the 5 possible colors is calculated as:
5C2= 
5C2=10
The number of shirts that can be made by combining 2 of the 2 possible colors (B) and (V) is calculated as:
2C2=1
Then the probability is:
P( B and V)= 
=0.1= 10%
<span>a. y = x^2 – 81 is a quadratic function.
According to the definition:
A quadratic function is defined as a function with the maximum coefficient of 2.Only first option has a coefficient of 2 and the rest have not.</span>
Answer:
x = √(a(a+b))
Step-by-step explanation:
We can also assume a > 0 and b > 0 without loss of generality. (If a and a+b have opposite signs, the maximum angle is 180° at x=0.)
We choose to define tan(α) = -(b+a)/x and tan(β) = -a/x. Then the tangent of ∠APB is ...
tan(∠APB) = (tan(α) -tan(β))/(1 +tan(α)tan(β))
= ((-(a+b)/x) -(-a/x))/(1 +(-(a+b)/x)(-a/x))
= (-bx)/(x^2 +ab +a^2)
This will be maximized when its derivative is zero.
d(tan(∠APB))/dx = ((x^2 +ab +a^2)(-b) -(-bx)(2x))/(x^2 +ab +a^2)^2
The derivative will be zero when the numerator is zero, so we want ...
bx^2 -ab^2 -a^2b = 0
b(x^2 -(a(a+b))) = 0
This has solutions ...
b = 0
x = √(a(a+b))
The former case is the degenerate case where ∠APB is 0, and the value of x can be anything.
The latter case is the one of interest:
x = √(a(a+b)) . . . . . . the geometric mean of A and B rotated to the x-axis.
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<em>Comment on the result</em>
This result is validated by experiments using a geometry program. The location of P can be constructed in a few simple steps: Construct a semicircle through the origin and B. Find the intersection point of that semicircle with a line through A parallel to the x-axis. The distance from the origin to that intersection point is x.
