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3 years ago

How to work out 5-(-11) modulus equations?

1 answer:

Vikki [24]3 years ago

6 0

ANSWER: 16.

A negative cancels out another negative. Therefore 5+11=16

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Firlakuza [10]

40 is the answer
5 x8 =40

3 0

2 years ago

maks197457 [2]

The correct answer is 5 hours

7 0

2 years ago

irina1246 [14]

If RY + YC = RC
7x+4=10x-2
3x=6
x=2
18+18=36=RC
The value of RC is 36

5 0

3 years ago

MrMuchimi

Answer:

${x}^{2} + 2xy + {y}^{2}$

Step-by-step explanation:

1) Use square sum: (a + b)² = a² + 2ab + b².

${x}^{2} + 2xy + y^{2}$

Therefor, the answer is x² + 2xy + y².

8 0

2 years ago

Lady_Fox [76]

Answer:

$\boxed{\bold{\huge{\boxed{497}}}}$

Step-by-step explanation:

=> $\sf 249^2 - 248^2$

Using Formula $\sf a^2 - b^2 = (a+b)(a-b)$

Where

a = 249

b = 248

=> $\sf (249+248)(249-248)$

=> $\sf (497)(1)$

=> 497

3 0

2 years ago