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hammer [34]
3 years ago
6

How to work out 5-(-11) modulus equations?

Mathematics
1 answer:
Vikki [24]3 years ago
6 0
ANSWER: 16.

A negative cancels out another negative. Therefore 5+11=16


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Simplify the following expression<br>(x+y)²​
MrMuchimi

Answer:

{x}^{2}  + 2xy +  {y}^{2}

Step-by-step explanation:

1) Use square sum: (a + b)² = a² + 2ab + b².

{x}^{2}  + 2xy + y^{2}

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>2xy</u><u> </u><u>+</u><u> </u><u>y</u><u>²</u>.

8 0
2 years ago
Using appropriate properties, find the value of 249² - 248²
Lady_Fox [76]

Answer:

\boxed{\bold{\huge{\boxed{497}}}}

Step-by-step explanation:

=> \sf 249^2 - 248^2

<u>Using Formula</u> \sf a^2 - b^2 = (a+b)(a-b)

<u><em>Where </em></u>

a = 249

b = 248

=> \sf (249+248)(249-248)

=> \sf (497)(1)

=> 497

3 0
2 years ago
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