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KonstantinChe [14]
2 years ago
11

Convert the following Standard Form equation to an equation in General For (x-7)^2 + (y + 3)^2 = 49​

Mathematics
2 answers:
S_A_V [24]2 years ago
7 0

Answer:

x² + y² - 14x + 6y + 9 = 0

Step-by-step explanation:

the equation of a circle in general form is

x² + y² + 2gx + 2fy + c = 0

given

(x - 7)² + (y + 3)² = 49 ← expand factors using FOIL

x² - 14x + 49 + y² + 6y + 9 = 49 , that is

x² + y² - 14x + 6y + 58 = 49 ( subtract 49 from both sides )

x² + y²- 14x + 6y + 9 = 0 ← in general form

Harman [31]2 years ago
4 0

Answer:

x+y=11

Step-by-step explanation:

take the square root of both sides.

(x-7) + (y+3) = 7

collect like terms

x+y = 7+7-3

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Andy completes the square for the equation x2 + 6x - 8 = 0. Which of the following equations reveals the vertex of the parabola?
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If the equation x^2+6x-8 has undergo completing the square, the answer would be:
x^2+6x-8

x^2+6x+9-8-9
**In this example, since 6x is the middle term, what comes to my mind is the polynomial (x+3) because 2ab results into 6x. [from the special products lesson (a+b)^2=a^2+2ab+b^2 ] 
(x+3)^2 -17 = 0
So if the equation is equal to y, then this equation's
y+17=(x+3)^2
The vertex would be on the point (-3, -17)
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3 years ago
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Step-by-step explanation:

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3 years ago
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Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the
ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}&#10;And in order to find the sample mean we just need to use this formula:&#10;[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

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In two gallons would be 8 quarts.

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Step-by-step explanation:

I hope this helps!

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