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lilavasa [31]
3 years ago
15

What are the values of x, y, and z in this system of equations?

Mathematics
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

{x,y,z}={5,−3,3}

Step-by-step explanation:

  [1]    2x + 4y + z = 1

  [2]    x - 2y - 3z = 2

  [3]    x + y - z = -1

// Solve equation [3] for the variable  y  

 [3]    y = -x + z - 1

// Plug this in for variable  y  in equation [1]

  [1]    2x + 4•(-x +z -1) + z = 1

  [1]    -2x + 5z = 5

// Plug this in for variable  y  in equation [2]

  [2]    x - 2•(-x +z -1) - 3z = 2

  [2]    3x - 5z = 0

// Solve equation [2] for the variable  x  

 [2]    3x = 5z

 [2]    x = 5z/3

// Plug this in for variable  x  in equation [1]

  [1]    -2•(5z/3) + 5z = 5

  [1]    5z/3 = 5

  [1]    5z = 15

// Solve equation [1] for the variable  z  

  [1]    5z = 15

  [1]    z = 3

// By now we know this much :

   x = 5z/3

   y = -x+z-1

   z = 3

// Use the  z  value to solve for  x  

   x = (5/3)(3) = 5

// Use the  x  and  z  values to solve for  y  

 y = -(5)+(3)-1 = -3

Solution :

{x,y,z} = {5,-3,3}

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Step-by-step explanation:

sqrt(49)

What number multiplied by itself = 49

7*7 = 49

-7*-7 = 49

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3 years ago
Bass Pro has a sale on boats! Just what you have always wanted and it is $3000 cheaper than it usually
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$4500

Step-by-step explanation:

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4 0
4 years ago
Calculate the distance between the points L=(-4,-1) and E =(3, 7) in the coordinate plane.
BaLLatris [955]

Answer:

10.6301458127

Step-by-step explanation:

Distance between any two points (x1, y1) and (x2,y2)  on a coordinate plane is expressed by the formula = \sqrt{(x1-x2)^2 + (y1 - y2)^2} \\

given  L=(-4,-1) and E =(3, 7

substituting value of coordinates in equation \sqrt{(x1-x2)^2 + (y1 - y2)^2} \\

we have

\sqrt{(-4 - 3)^2 + (-1 - 7)^2} \\=>\sqrt{(-7)^2 + (-8)^2} \\=>\sqrt{49 + 64} \\=>\sqrt{113} \\=>10.6301458127

Therefore  the distance between the points L=(-4,-1) and E =(3, 7) = 10.6301458127

4 0
3 years ago
Italia spent 3/4 of this week's allowance on candy. Of the money she spent on candy, 5/6 was spent on gummy bears. What fraction
jasenka [17]
Let
x-----------> <span>this week's allowance

we know that
(3/4)x-----------> </span><span>was spent on candy
and
(5/6)[</span>(3/4)x]-------> <span>was spent on gummy bears
(5/6)*(3/4)x=(15/24)x------> (5/8)x

the answer is
5/8</span>
7 0
3 years ago
Lol help me for a brainliest
Dmitrij [34]

Answer:  \bold{b)\quad \dfrac{17}{36}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{1}{6}\bigg(2\dfrac{1}{3}-\dfrac{3}{4}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{7}{3}-\dfrac{3}{4}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{28}{12}-\dfrac{9}{12}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{19}{12}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{19}{72}+\dfrac{5}{24}\\\\\\=\dfrac{19}{72}+\dfrac{15}{72}\\\\\\=\dfrac{34}{72}\\\\\\=\large\boxed{\dfrac{17}{36}}

3 0
3 years ago
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