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eduard
3 years ago
13

How would I solve this?

Mathematics
1 answer:
Serhud [2]3 years ago
8 0

x^2-36\not =0\\x^2\not =36\\x\not =-6 \wedge x\not =6\\\\D_f:x\in\mathbb{R}\setminus\{-6,6\}

Interval notation:

D_f:x\in(-\infty-6)\cup(6,\infty)


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