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3 years ago

Add. Simplify your answer. 3y^2/y+1 + 3y/y+1

1 answer:

5 0

$\dfrac{3y^2}{y+1}+\dfrac{3y}{y+1}=\dfrac{3y^2+3y}{y+1}=\dfrac{3y(y+1)}{y+1}=3y\to\fbox{B.}\\\\\\\dfrac{c+5}{3c+3}-\dfrac{4}{3c+3}=\dfrac{c+5-4}{3c+3}=\dfrac{c+1}{3c+3}=\dfrac{c+1}{3(c+1)}=\dfrac{1}{3}\to\fbox{D.}$

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What is the quotient of d − 2 √ d 4 − 5 d 3 + d + 17

Tcecarenko [31]

Answer: $d^3 - 3d^2-5$

Step-by-step explanation:

For finding the quotient of the given division,

In the long division method, we will follow the following steps.

Step 1 : Here the divisor is d-2 and dividend is $d^4-5 d^3 + d + 17$

Multiply (d-2) by $d^3$ and subtract the dividend by the resultant.

We get $-3d^3+d$

Step 2: Multiply (d-2) by $-3d^2$ and subtract the remaining dividend by the resultant.

We get $-5d^2+17$

Step 3 : Multiply (d-2) by $-5$ and subtract the remaining dividend by the resultant.

We get $7$

Since, after getting 7 it is not possible further division,

Hence, Remainder = 7,

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Sever21 [200]

Answer:

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Step-by-step explanation:cuz why not

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