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2 years ago

Add. Simplify your answer. 3y^2/y+1 + 3y/y+1

1 answer:

5 0

$\dfrac{3y^2}{y+1}+\dfrac{3y}{y+1}=\dfrac{3y^2+3y}{y+1}=\dfrac{3y(y+1)}{y+1}=3y\to\fbox{B.}\\\\\\\dfrac{c+5}{3c+3}-\dfrac{4}{3c+3}=\dfrac{c+5-4}{3c+3}=\dfrac{c+1}{3c+3}=\dfrac{c+1}{3(c+1)}=\dfrac{1}{3}\to\fbox{D.}$

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2 years ago

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