(0,3) because if you go up six on the Y axis you get three. If you go two over on the X axis you reach zero.
Answer: (c)
Step-by-step explanation:
Given
The expression is ![3x^2-7](https://tex.z-dn.net/?f=3x%5E2-7)
checking options, for (a)
![\Rightarrow 2x^2-11-x-4\\\Rightarrow 2x^2-x-15](https://tex.z-dn.net/?f=%5CRightarrow%202x%5E2-11-x-4%5C%5C%5CRightarrow%202x%5E2-x-15)
option (a) is incorrect
for (b)
![\Rightarrow 5x^2-6-2x^2+1\\\Rightarrow 3x^2-5](https://tex.z-dn.net/?f=%5CRightarrow%205x%5E2-6-2x%5E2%2B1%5C%5C%5CRightarrow%203x%5E2-5)
option(b) is incorrect
for (c)
![\Rightarrow 10x^2-4-7x^2-3\\\Rightarrow 3x^2-7](https://tex.z-dn.net/?f=%5CRightarrow%2010x%5E2-4-7x%5E2-3%5C%5C%5CRightarrow%203x%5E2-7)
option (c) is matching with the given expression.
Answer:
x=0
Step-by-step explanation:
x^2-8x-2=0
x=±3√2−4
Answer:
The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2
Step-by-step explanation:
Given that the spinner has 12 equal sections labelled 1-12
Let S be the sample space
Then
S = {1,2,3,4,5,6,7,8,9,10,11,12}
![n(S) = 12](https://tex.z-dn.net/?f=n%28S%29%20%3D%2012)
Let A be the event that the outcome is an even number
Then
A = {2,4,6,8,10,12}
![n(A) = 6](https://tex.z-dn.net/?f=n%28A%29%20%3D%206)
The probability of A will be given as:
![p(A) = \frac{n(A)}{n(S)}\\\\= \frac{6}{12}\\\\= \frac{1}{2}](https://tex.z-dn.net/?f=p%28A%29%20%3D%20%5Cfrac%7Bn%28A%29%7D%7Bn%28S%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B6%7D%7B12%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7B2%7D)
Hence,
The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2