3 years ago

Suppose you spin the spinner and toss a coin. What is the probability of NOT heads and NOT 4? A) 1/8 B) 3/8 C) 5/8 D) 7/8

1 answer:

8 0

I think the answer is B) $\frac{3}{8}$ . You can figure this out by multiplying the possible outcomes of the coin by the spinner (4*2) and find the amount of outcomes that are not what you are looking for (3) and put that over the product. (3/8)

Hope this helps

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Answer:

$f(x)=(x-4.5)^{2}-6.25$ or $f(x)=(1/4)(2x-9)^{2}-6.25$

Step-by-step explanation:

we have

$f(x)=x^{2}-9x+14$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-14=x^{2}-9x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-14+4.5^{2}=x^{2}-9x+4.5^{2}$

$f(x)+6.25=x^{2}-9x+4.5^{2}$

Rewrite as perfect squares

$f(x)+6.25=(x-4.5)^{2}$

$f(x)=(x-4.5)^{2}-6.25$

$f(x)=(1/4)(2x-9)^{2}-6.25$

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Bad White [126]

Answer:

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