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3 years ago

Find the exact and the approximate volume of the cylinder. Round your approximation to the nearest hundredth. Show all work.

Mathematics

2 answers:

aalyn [17]3 years ago

8 0

V=hieght times pi times radius^2
diameter/2=radius
12/2=6=radius
height=10

v=10*pi*6^2
v=10*pi*36
V=360pi
using pi=3.141592
V=1130.97312
round
V=1130.97 cubic centimeters

Degger [83]3 years ago

5 0

V=hpr^2

V=10p(12/2)^2

V=360p cm^3 exact

V=1131 cm^3 (to the nearest tenth of a cubic centimeter)

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nlexa [21]

Answer:

Step-by-step explanation: partial derivative is the differentiation of one variable e.g. X while leaving the values of the other variable e.g. Y

These four questions A, B, C and D have different functions separated by commas. I will not assume the commas to be something else like a plus sign.

A. f(x) = g'(x).k(y) , g'(x) + h(y)

f(y) = k'(y).g(x) , g(x) + h'(y)

B. f(x) = g'x (x+y)

f(y) = g'y (x+y) , h'y (y+z)

f(z) = h'z (y+z)

C. f(x) = f'x (xy) , f'x (zx)

f(y) = f'y (xy) , f'y (yz)

f(z) = f'z (yz) , f'z (zx)

D. f(x) = f'x (x) , g'(x) , h'x (x,y)

f(y) = h'x (x,y)

These are the partial derivative expressions for each variable in each function. You will need to pay a lot of attention to understand:

* while differentiating X alone, functions in Y which are separated by commas from the functions in X, are ignored totally because they are different questions

* In functions where X added to Y is in a bracket e.g. (x+y), to find the derivative of X, Y isn't thrown away because they are joined (by a plus sign) the derivative of X alone in this case would be f'x (x+y)

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3 years ago

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Savatey [412]

Answer:

b = 87°

Step-by-step explanation:

In order to answer this question, we need to utilise an important angle fact which is <em>angles in a quadrilateral add up to 360° </em>

Using the information we can set up an equation to find the value of b

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Step-by-step explanation:

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Irina-Kira [14]

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ikadub [295]

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