Question:
Vincent bought a 25-pound bag of rice. He cooked 6.25 pounds of the rice. He stored the rest of the rice in
- pound portions. What is the maximum number of
- pound portions he stored?
Answer:
The maximum number of portion he stored is 5 portion
Step-by-step explanation:
Given
Size of Rice = 25 lb
Size of Cooked Rice = 6.25 lb
Portions saved =
lb
Required
Number of portion saved;
First, the size of rice after cooking needs to be calculated;
If 6.25lb of rice was cooked from a total of 25lb;
Then, the size of rice left is
![Size = 25lb - 6.25lb](https://tex.z-dn.net/?f=Size%20%3D%2025lb%20-%206.25lb)
![Size = 18.75lb](https://tex.z-dn.net/?f=Size%20%3D%2018.75lb)
Now that we have the amount left after cooking; we can simply calculate the maximum number of portions;
This is calculated by dividing size of rice left by portions of saved rice;
i.e.
Maximum number of portion = Size of rice left / Portions of saved rice
Maximum number of portion = ![\frac{18.75lb}{3\frac{3}{4}lb}](https://tex.z-dn.net/?f=%5Cfrac%7B18.75lb%7D%7B3%5Cfrac%7B3%7D%7B4%7Dlb%7D)
Convert
to mixed fraction
Maximum number of portion = ![\frac{18.75lb}{\frac{15}{4}lb}](https://tex.z-dn.net/?f=%5Cfrac%7B18.75lb%7D%7B%5Cfrac%7B15%7D%7B4%7Dlb%7D)
Maximum number of portion = ![\frac{18.75}{\frac{15}{4}}](https://tex.z-dn.net/?f=%5Cfrac%7B18.75%7D%7B%5Cfrac%7B15%7D%7B4%7D%7D)
Rewrite expression
Maximum number of portion = ![18.75 / \frac{15}{4}](https://tex.z-dn.net/?f=18.75%20%2F%20%5Cfrac%7B15%7D%7B4%7D)
Change divide (/) sign to multiplication (*)
Maximum number of portion = ![18.75 * \frac{4}{15}](https://tex.z-dn.net/?f=18.75%20%2A%20%5Cfrac%7B4%7D%7B15%7D)
Maximum number of portion = ![\frac{75}{15}](https://tex.z-dn.net/?f=%5Cfrac%7B75%7D%7B15%7D)
Maximum number of portion = 5
Hence, the maximum number of portion he stored is 5 portions