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Sergeeva-Olga [200]
3 years ago
10

An arrow on a spinner is spun 250 times. Some of the results are shown below. The relative frequency of landing on a 4 is the sa

me as the relative frequency of landing on a 5 Work out the relative frequency of landing on a 4

Mathematics
1 answer:
N76 [4]3 years ago
5 0

Answer:

11/50

Step-by-step explanation:

The frequency numbers for landing on 1, 2, and 3 are:

25, 53, 62.

We add them up to get: 25 + 53 + 62 = 140

Since 250 spins were made, and 140 of them landed on 1, 2, or 3, then

250 - 140 = 110,

so 110 landed on 4 or 5.

We are told the numbers of spins landing on 4 and 5 are equal, so

110/2 = 55,

so the spinner landed 55 times on 4 and 55 times on 5.

relative frequency = 55/250 = 11/50

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Even though, there are more numbers, the question only asked for the ratio of books to pencils.

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a quarterback throws a football from a height of 6 feet with an initial velocity of 20 feet per seconds. the height (h) of the b
kirza4 [7]

The range of the function is from 2 feet to 12.25 feet

Step-by-step explanation:

In a function f(x) = y

  • x is the domain of the function
  • y is the range of the function

The height (h) of the ball at time (t) seconds can be represented by the equation h(t) = - 16 t² + 20 t + 6

∵ h(t) = - 16 t² + 20 t + 6

∴ The domain is t

∴ The range is h(t)

- To find the range of the quadratic function find the maximum or

   minimum value of it

∵ The leading coefficient of the function is -16

∴ The function has a maximum value

To find the maximum value differentiate h(t) with respect to t and equate it by 0 to find the value of t for the maximum height

∵ h'(t) = -16(2) t + 20(1)

∴ h'(t) = -32 t + 20

- Equate it by 0

∵ h'(t) = 0

∴ -32 t + 20 = 0

- Subtract 20 from both sides

∴ -32 t = - 20

- Divide both sides by -32

∴ t = 0.625 seconds ⇒ time for the maximum height

Substitute the value of t in h(t) to find the maximum height

∵ h(0.625) = -16(0.625)² + 20(0.625) + 6

∴ h(t) = 12.25 feet

∴ The maximum height of the ball is 12.25 feet

∵ The ball is caught at 2 feet

∴ The range of the function is 2 ≤ h(t) ≤ 12.25

The range of the function is from 2 feet to 12.25 feet

Learn more:

You can learn more about the quadratic equations in brainly.com/question/9390381

#LearnwithBrainly

8 0
3 years ago
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