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Sergeeva-Olga [200]
2 years ago
10

An arrow on a spinner is spun 250 times. Some of the results are shown below. The relative frequency of landing on a 4 is the sa

me as the relative frequency of landing on a 5 Work out the relative frequency of landing on a 4

Mathematics
1 answer:
N76 [4]2 years ago
5 0

Answer:

11/50

Step-by-step explanation:

The frequency numbers for landing on 1, 2, and 3 are:

25, 53, 62.

We add them up to get: 25 + 53 + 62 = 140

Since 250 spins were made, and 140 of them landed on 1, 2, or 3, then

250 - 140 = 110,

so 110 landed on 4 or 5.

We are told the numbers of spins landing on 4 and 5 are equal, so

110/2 = 55,

so the spinner landed 55 times on 4 and 55 times on 5.

relative frequency = 55/250 = 11/50

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The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds
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The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation h=-16t^2+24t+16, where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation h=-16t^2+24t+16, we get,

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t=2

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