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lara [203]
2 years ago
11

Point Q is plotted on the coordinate grid. Point P is at (30, −30). Point R is vertically above point Q. It is at the same dista

nce from point Q as point P is from point Q. Which of these shows the coordinates of point R and its distance from point Q? On a coordinate grid from negative 50 to positive 50 in increments of 10, Point Q is plotted at the ordered pair negative 40, negative 30.

Mathematics
1 answer:
pogonyaev2 years ago
8 0

Answer:

Point R in coordinate (graph)

d_{QR}=70units

Step-by-step explanation:

According to the graph,  distance betwen QR=(Y2-Y1) = 40-(-30) →

d_{QR}=70units

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An angle measures 118° less than the measure of a supplementary angle. What is the measure of each angle
Alex787 [66]
Supplementary angles add up to 180°

x = greater supplementary angle
x - 118 = lesser angle

x + (x - 118) = 180
2x - 118 = 180
2x = 298
x = 149

x - 118
149 - 118 = 31

the angles are 31° and 149°
4 0
3 years ago
Paulo works at the United Nations. He researched what percent of the world's population lives on each continent. He surveys a sa
Fofino [41]

Answer:

confidence interval using a  two sample t test between percents

Step-by-step explanation:

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5 0
3 years ago
Find the coordinates of the missing endpoint if B is the midpoint of AC. C(-6,-2),B(-3,-5)
Margaret [11]

Answer:

  A = (0, -8)

Step-by-step explanation:

  B = (A+C)/2 . . . . the midpoint is the average of the end points

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5 0
2 years ago
the volume of cube A is 216 cubic inches. the length of each edge in cube B is 2 inches longer than the length of each edge in c
Aleonysh [2.5K]
If the side lengths of B are 2x as long as the side lengths of A then the volume of B should be the volume of A^2
216^2=46,656
46,656-216=46,440

This can be more easily displayed with smaller numbers

If cube X were 2*2*2 then the volume would be 8
If cube Y were 4*4*4 then the volume would be 64
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7 0
3 years ago
Solve the system by elimination <br> 2x+6y= -12 <br> 5x-5y= -10
kvv77 [185]
First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier. 
Eliminate 'x' variable by subtracting 2nd equation from 1st.

   x + 3y = -6
-(x  - y = 2)
----------------------
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Solve for 'y'
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Substitute value for 'y' back into 2nd equation:
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x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

5 0
3 years ago
Read 2 more answers
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