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vitfil [10]
3 years ago
11

A worker pushes a wheelbarrow with a force of 20N downward and to the left, as shown in the figure below. The angle the handle m

akes with the horizontal is 34°. Note that the figure is not drawn to scale. Write the force vector F in the form =F+aibj. Do not round any intermediate computations, and round the values in your answer to the nearest hundredth. f=
Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer:

The values of F will be "16.58 i + 11.18 j".

Step-by-step explanation:

The given values are:

Force, F = 20 N

Angle, Ф = 33°

The formula use in the given scenario will be:

⇒  x=a \ Cos\theta

⇒  y=a \ Sin\theta

Now,

For Force, F=ai+bj

⇒  a=F \ Cos\theta

⇒     =20 \ Cos(34^{\circ})

⇒     =20\times .829

⇒     =16.58

and,

⇒  b=F \ Sin\theta

⇒     =20 \ Sin(34^{\circ})

⇒     =20\times .55

⇒     =11.18

So that,

⇒  F=16.58 \ i+11.18 \ j

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