Question

A worker pushes a wheelbarrow with a force of 20N downward and to the left, as shown in the figure below. The angle the handle makes with the horizontal is 34°. Note that the figure is not drawn to scale. Write the force vector F in the form =F+aibj. Do not round any intermediate computations, and round the values in your answer to the nearest hundredth. f=

Answer 1

Answer:

The values of F will be "16.58 i + 11.18 j".

Step-by-step explanation:

The given values are:

Force, F = 20 N

Angle, Ф = 33°

The formula use in the given scenario will be:

⇒  $x=a \ Cos\theta$

⇒  $y=a \ Sin\theta$

Now,

For Force, $F=ai+bj$

⇒  $a=F \ Cos\theta$

⇒     $=20 \ Cos(34^{\circ})$

⇒     $=20\times .829$

⇒     $=16.58$

and,

⇒  $b=F \ Sin\theta$

⇒     $=20 \ Sin(34^{\circ})$

⇒     $=20\times .55$

⇒     $=11.18$

So that,

⇒  $F=16.58 \ i+11.18 \ j$