A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
Answer: = -2/4x + -1/2
Step-by-step explanation:
hope this helped
I do believe the answer is 52, sorry if i’m incorrect
Answer:
SAS (side angle side)
Step-by-step explanation:
We have a pair of corresponding sides and the included angle. The angle is equal, but the sides are a fraction of the other triangle's side and has an equal rate.
2AC=DF
2AB=DE
The triangles are congruent
