Angle DEF measures 75°. What is the measure of angle CFD? 105° 125° 150° 165°

If (14,25) and (9,-10) are two anchor points on a trend line, then find the equation of the line.

posledela

Answer:

y= 7x-73

Step-by-step explanation:

the equation form is y=mx+c where m is the slope and c a constant

m= (25-(-10))/14-9 = 35/5 = 7

so y= 7x+c

replace x and y by 14 and 25 respectively

25 = 7*14+c

c= 25-7*14

c = -73

so y= 7x-73

3 0

2 years ago

Show that 5^133 +26 is a multiple of 31

MArishka [77]

Answer:

3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45

Step-by-step explanation:

4 0

2 years ago

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On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)

goldfiish [28.3K]

Answer:

f(x) > 0 over the interval $(-\infty,-4)$

Step-by-step explanation:

If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from $- \infty$ , until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from $- \infty$ to -3, since between the values -4 and -3 the function adopts negative values.

6 0

2 years ago

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26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics

hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

$\mu _d = \mu _{post} - \mu _{pre}$

Then the null hypotheses and alternative hypotheses will be

H₀: $\mu _d = 0$

Hₐ: $\mu _d > 0$

Then the test statistic will be

$\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5$

Then

$\rm S_d = 6.02$

The test statistic value is given by

$\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16$

Since this is a right-tailed test, so the critical value is given by

$\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353$

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that $\mu _d > 0$ that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0

1 year ago

If you have 8 marbles (5 green and 3 blue), what is the probability of drawing a green, then 2 blues, and then a green without a

kifflom [539]

The answer of this question is B

4 0

2 years ago