Does anyone know the answer to this?!

Mathematics

2 answers:

devlian [24]3 years ago

8 0

Answer:

65°

Step-by-step explanation:

Properties of a triangle:

Triangles always have 3 sides
The sum of the interior angles of a triangle must be equal to 180°.

To solve:

Since the angles inside of a triangle must always be equal to 180, use the following formula to solve:
a + b + c = 180
(The variables can be assigned to any value in this situation)
Since two angles are already given, replace 2 variables:
a + 85 + 30 = 180
Solve the equation by subtracting on both sides:
a = 65
The value of a is the measure of the missing angle. The problem is solved.

dangina [55]3 years ago

8 0

Answer:

the missing angle is 65

Step-by-step explanation:

a whole triangle is 180

subtract the given angles from 180

180

- 85

----------

95

subtract the remaining angle

95

- 30

---------

65

~hope this helped :3~

You might be interested in

What are the steps to solve the quadratic equation x^2+4x-6=0

makvit [3.9K]

$METHOD\ 1:\\\\Use:\\\\(*)\qquad(a+b)^2=a^2+2ab+b^2\\---------------------\\\\x^2+4x-6=0\qquad\text{add 6 to both sides}\\\\x^2+4x=6\\\\x^2+2(x)(2)=6\qquad\text{add}\ 2^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(2)+2^2}_{(*)}=6+2^2\\\\(x+2)^2=6+4\\\\(x+2)^2=10\Rightarrow x+2=\pm\sqrt{10}\qquad\text{subtract 2 from both sides}\\\\\boxed{x=-2-\sqrt{10}\ \vee\ x=-2+\sqrt{10}}$

$METHOD\ 2:\\\\\text{use the quadratic formula:}\\\\ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta>0,\ \text{the equation has two solutions}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\if\ \Delta=0,\ \text{then the equation has one solution:}\ x=\dfrac{-b}{2a}\\\\if\ \Delta$

$x^2+4x-6=0\\\\a=1,\ b=4,\ c=-6\\\\\Delta=4^2-4(1)(-6)=16+24=40>0\\\\\sqrt\Delta=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}\\\\x_1=\dfrac{-4-2\sqrt{10}}{2(1)}=\dfrac{-4}{2}-\dfrac{2\sqrt{10}}{2}=-2-\sqrt{10}\\\\x_2=\dfrac{-4+2\sqrt{10}}{2(1)}=\dfrac{-4}{2}+\dfrac{2\sqrt{10}}{2}=-2+\sqrt{10}$