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lara31 [8.8K]
2 years ago
10

What is 286 over 465 in simplest form?

Mathematics
1 answer:
Sholpan [36]2 years ago
7 0
\frac{286}{465
}
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A group of friends share 32 cookies.
Stels [109]

Answer:

8

Step-by-step explanation:

32-jessica(8)-garret(8)=16, If John eats 8 more cookies, then there are only 8 cookies left.

8 0
3 years ago
Determine weather the rule represents an exponential function. EASY 40 POINTS
joja [24]
<h3>Answer: Since the independent variable x is not the exponent, y = 3x^3 is <u>not</u> an exponential function (choice D)</h3>

Exponential functions are something like y = 2^x where the variable is in the exponent (ie the exponent isnt a fixed number). What is given here, y = 3x^3, is a cubic function. You can also call this a power function. Power functions are of the form a*x^b, where a & b are constants.

5 0
2 years ago
What’s the result ????????????????
Mrrafil [7]

Answer:

Option 1

Step-by-step explanation:

You must multiply (2x + 3) by (x + 4). I use the FOIL method.

(2x + 3)(x + 4)

Multiply

2x² + 8x +3x + 12

Simplify

2x² + 11x + 12

To check the answer, you could factor this trinomial back into a pair of binomials.

4 0
2 years ago
**PLEASE HELP**
maksim [4K]

Answer:

Number 4

Step-by-step explanation:

Option B would yield more in the short term but after Option A surpasses it, it would become more profitable.

6 0
2 years ago
For the piecewise function, find the values h( - 6), h(0), h(5), and h(9).- 5x – 13, for x &lt; -3h(x) = { 5, for - 35x&lt;5for
sleet_krkn [62]

Given the piecewise function h(x):

h(x)=\begin{cases}-5x-13,x

-When x is less than "-3", h(x)=-5x-13

-When x is between -3 and 5, h(x)=5

-When x is greater than or equal to 5, h(x)=x+1

1) For h(-6), this notation indicates that you have to determine the value of h(x) when x=-6

-6 is less than -3, which means that for this value of x, the function has the following shape

h(x)=-5x-13

Replace the expression with x=-6 and calculate the corresponding value of x:

\begin{gathered} h(-6)=-5(-6)-13 \\ h(-6)=30-13 \\ h(-6)=17 \end{gathered}

2) For h(0), you have to determine the value of h(x) when x=0. Zero is between -3 and 5, for this value of x, the function h(x) has the following shape:

h(x)=5

This equation represents a horizontal line, which means that for every value within the interval of definition -3≤x<5, the function always has the same value h(x)=5

We can conclude that:

h(0)=5

3) For h(5), you have to determine the value of h(x) for x=5, for values of x greater than or equal to 5, h(x) has the following shape:

h(x)=x+1

Replace the expression with x=5 and calculate the corresponding value of h(x):

\begin{gathered} h(5)=5+1 \\ h(5)=6 \end{gathered}

4) For h(9), you have to determine the value of h(x) when x=9, 9 is greater than 5, for this value of x, the function has the following shape:

h(x)=x+1

Replace the expression with x=9, and calculate the corresponding value of h(x):

\begin{gathered} h(9)=9+1 \\ h(9)=10 \end{gathered}

So, to sum up:

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5 0
1 year ago
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