Answer:
0.010
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score = 63 inches
μ is the population mean = 70 inches
σ is the population standard deviation = 3 inches
For x shorter than 63 inches = x < 63
Z score = x - μ/σ
= 63 - 70/3
= -2.33333
Probability value from Z-Table:
P(x<63) = 0.0098153
Approximately to the nearest thousandth = 0.010
Therefore, the probability that a randomly selected student will be shorter than 63 inches tall, to the nearest thousandth is 0.010.
Divide both sides by l. Hope this helps! :D
Answer:
The solutions are the following:
- z=2(cos(π6)+isin(π6))=√3+12i
- z=2(cos(2π3)+isin(2π3))=−1+i√3
- z=2(cos(7π6)+isin(7π6))=−√3−12i
- z=2(cos(5π3)+isin(5π3))=1−i√3
<em>hope this helps!! :) --Siveth</em>
Answer:
210
Step-by-step explanation:
Lets use BEDMAS (Brackets, Exponents, Division, Multiplication, Addition, Subtraction)
45 ÷ 2 = 22.5
22.5 × 8 = 180
180 - 12 = 168
168 + 42 = 210
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Have a great summer :)
