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FrozenT [24]
2 years ago
15

Is 13 a prime or composite

Mathematics
2 answers:
eimsori [14]2 years ago
4 0

Answer:

13 would be a prime number.

Step-by-step explanation:

Trust me :)

kodGreya [7K]2 years ago
3 0

Answer:

Prime

Step-by-step explanation:

Prime numbers are numbers that have only 2 factors 1 and themselves. In 13's case, the only way of getting a product which is 13, is 13x1 and 1x13.

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ANSWER ASAP PLEASE!! OTHER ANSWER CHOICES ARE 5/12 and 7/12.BRAKE DOWN!!
Yuri [45]

Answer:

A=1/12

Step-by-step explanation:

3/4-2/3=3*3/4*3-2*4/3*4=9/12-8/12=1/12

6 0
4 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
Blababa [14]

Answer:

Step-by-step explanation:

so when the height is zero, that's when the rocket hits the ground.  The equation will have two zeros,  but one would be for a negative time,  or before the rocket is launched.    so we only one the one after the rocket is launched.

use the quadratic formula to solve for  x  ( which is time)

-124 +- sqrt [ 124^{2} - 4*(-16)*(127) ] / 2 (-16)

-124 +- sqrt [15376 + 8128 ] / -32

-124 +- sqrt [23504 ] / -32

-124 +- 153.310 / -32

if we take the positive part it will become the negative time so skip that one try the negative part 1st

-124 - 153.310 / -32

-277.310 / -32

8.6659 seconds to hit the ground.    ( time of flight)  aka   TOF

8.67 seconds  ( rounded to nearest 100th)

 

3 0
3 years ago
Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem. A cube-shaped contain
Nesterboy [21]
12167 feet squared.......
8 0
3 years ago
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
4 years ago
Someone please help me
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There’s nothing there
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3 years ago
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