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2 years ago

The sum of two number is 91. The smaller number is thirteen less than the large number. Find both numbers.

1 answer:

7 0

What you would do is make the equation:
91=X+(X-13)
Then, you would solve for X and once you find X, you would subtract 13 from it.
The answers should be 52 and 39.

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Solve and graph the inequality on a number line -19>g-24

Lorico [155]

Do, 24 + -19

= 5

-19 > 5

-19 is bigger than 5

So the answer is
g = 5

7 0

2 years ago

Evaluate <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5E%7B-2%7Dx%5E%7B-3%7Dy%5E%7B5%7D%20%7D" id="TexFormula1" title="\

Irina18 [472]

Answer:

$\bf C)\: -\cfrac{1}{32}$

Step-by-step explanation:

$\tt \cfrac{1}{2^{-2}x^{-3}y^5}$

$\tt x=2\\y=-4$

Substitute ''x'' with '2' & 'y' with "-4":-

$\tt \cfrac{1}{2^{-2}\times \:2^{-3}\left(-4\right)^5}$

First let's solve $\tt 2^{-2}\times \:\:2^{-3}\left(-4\right)^5$

$\tt 2^{-2}\times \:2^{-3}=\boxed{\cfrac{1}{32} }$

$\tt \cfrac{1}{32}\left(-4\right)^5$

Calculate exponents:- -4^5= -1024

$\tt \cfrac{1}{32}\left(-1024\right)$

Remove parentheses, apply rule:- $\tt a\left(-b\right)=-ab$

$\tt-\frac{1}{32}\times \:1024$

$\tt \cfrac{1}{32}\times \cfrac{1024}{1}$

Apply fraction rule:-

$\tt -\cfrac{1\times \:1024}{32\times \:1}$

$\tt \cfrac{1024}{32}$

Divide numbers:-

$\tt -32$

Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

$\tt -\cfrac{1}{32}\;\; \bf Answer$

3 0

2 years ago

Read 2 more answers

Let A = {10, 20, 30, 40, 50, 60} and B = {10, 40, 603. What is AnB

lorasvet [3.4K]

Answer: I DONT KNOW
Explanation: SORRY

5 0

3 years ago

Read 2 more answers

Number 8 please hurry

Hitman42 [59]

Answer:

A rational number is normally number that can be expressed in the form of p/q where q ≠ 0. But, $\sqrt{42}$ cannot be expressed in the form of p/q. So. this means that

(Can I have Brainliest please? It really helps me help more people in Brainly!)

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2 years ago

Plz helppp thank uuuu :)

djyliett [7]

Answer:

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2 years ago