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cricket20 [7]
3 years ago
7

(6,-1) and y = – 1/3x+ 1 y = 3x + [?]

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

- 19

Step-by-step explanation:

Let's consider the equation as ;

y = 3x + c

( 6, -1 ) satisfies the equation ;

-1 = 3( 6) + c

c = - 18 - 1

c = -19

So the slope - intercept is (- 19)

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garri49 [273]
The answer is B !!!!!!
5 0
3 years ago
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Choose the pair of numbers that is not a solution to the given equation.
balandron [24]

Answer:

The pair (0,3) is not a solution to the equation

Step-by-step explanation:

This can be proved by simply replacing the x and y variables in the equation by the x and y values of the pair, and checking if the equation renders a true statement:

By replacing x and y with their values in the pair (0,3), that is x=0 and y=3, in the equation y = 5 - 2x  we get:

3 = 5 - 2 (0)

3 = 5 - 0

3 = 5

which is NOT a true statement.

On the other hand, the other two pairs (2,1) and (1,3) render true statements:

1 = 5 - 2 (2)

1 = 5 - 4

1 = 1

and

3 = 5 - 2 (1)

3 = 5 - 2

3 = 3

3 0
4 years ago
a cookie recipe calls 3 1/4 cups of flour. the recipe makes 3 dozen cookies. how much flour us needed to make 144 cookies
Mnenie [13.5K]

1 dozen = 12

144 / 12 = 12 dozen

12 dozen/ 3 = 4

They need 4 times the amount of flour:

3 1/4 x 4 = 13

They need 13 cups of flour

4 0
3 years ago
Write each of the following as a function of theta.<br> 1.) sin(pi/4 - theta) 2.) tan(theta+30°)
Paladinen [302]

Step-by-step explanation:

Let x represent theta.

\sin( \frac{\pi}{4} - x )

Using the angle addition trig formula,

\sin(x - y)  =  \sin(x)  \cos(y)  -  \cos(x)  \sin(y)

\sin( \frac{\pi}{4} )  \cos(x)  -  \cos( \frac{\pi}{4} )  \sin(x)

( \frac{ \sqrt{2} }{2})  \cos(x)  -  (\frac{ \sqrt{2} }{2}  )\sin(x)

Multiply one side at a time

Replace theta with x , the answer is

\frac{ \sqrt{2} \cos(x)  }{2}  -  \frac{ \sin(x) \sqrt{2}  }{2}

2. Convert 30 degrees into radian

\frac{30}{1}  \times  \frac{\pi}{180}  =  \frac{\pi}{6}

Using tangent formula,

\tan(x + y)  =  \frac{ \tan(x)  +  \tan(y) }{1 -  \tan(x) \tan(y)  }

\frac{ \tan(x) +  \tan( \frac{\pi}{6} )  }{1 -  \tan(x) \tan( \frac{\pi}{6} )  }

Tan if pi/6 is sqr root of 3/3

\frac{ \tan(x) +  ( \frac{ \sqrt{3} }{3} )  }{1 -  \tan(x)  (\frac{ \sqrt{3} }{3} )  }

Since my phone about to die if you later simplify that,

you'll get

\frac{(3 \tan(x) +  \sqrt{3} )(3 +  \sqrt{3}  \tan(x)  }{3(3 -  \tan {}^{2} (x) }

Replace theta with X.

4 0
3 years ago
Simplify: -0.8b + 4.1c -(-3.2b) - 0.1c
umka21 [38]
-0.8b+4.1c-(-3.2b)-0.1c
-(-3.2b)= 3.2b
4.1c-0.1c=4c
-0.8b+4c+3.2b
-0.8b+3.2b=2.4b

4c+2.4b
3 0
3 years ago
Read 2 more answers
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