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san4es73 [151]
3 years ago
12

You are in a bike race. When you get to the first checkpoint you are 2/5 of the distance away to the second checkpoint. When you

get to the second checkpoint you are 1/4 of the distance to the finish. What is the distance from start to check point 1?
Mathematics
2 answers:
Ainat [17]3 years ago
7 0

Answer:

its 1/4

Step-by-step explanation:


gizmo_the_mogwai [7]3 years ago
6 0

the answer is 1/4 of a distance away

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The sum of two numbers is 66. two times the smaller number is 15 more then th larger number what are the numbers
Delicious77 [7]

Let x = big number

Let y = small number

x + y = 66...Equation A

2y = x + 15...Equation B

We have two equations in two unknowns.

x + x + 15 = 66

2x = 66 - 15

2x = 54

x = 54/2

x = 27

Plug x = 27 into EITHER equation above to find y.

I will use Equation A.

x + y = 66

27 + y = 66

y = 66 - 27

y = 39

The two numbers are 27 and 39.

6 0
3 years ago
Read 2 more answers
you earned $112.00 last time you babysat for 7 hours.The same family asks you to babysat for 8 hours this time.They will pay you
guapka [62]

You will earn $128.00 because when you divide $112.00 by 7 you get 16. Then you multply 16 by 8 and get $128.00

Hope I was helpful!

3 0
3 years ago
Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
3 years ago
On Monday, during a one day sale, the price of a suit was decreased by 20%. On Tuesday, the price of the suit was changed back t
nignag [31]

Answer:

25%

Step-by-step explanation:

If we consider the original price of the piece of suit is x.

Given that, on Monday during a one day sale, the price of the suit was decreased by 20%.

Therefore, the new price of the suit on Monday is x( 1 - \frac{20}{100}) = 0.8x.

Now, the price of the suit on Tuesday was changed back to the original price i.e. x.

Therefore, the price is increase by (x - 0.8x) = 0.2x from the price of 0.8x.

So, the percentage change in price of the suit on Tuesday is \frac{0.2x}{0.8x} \times 100 = 25%. (Answer)

8 0
3 years ago
-4 1/2x - 3/7= 1/4<br>find x
DiKsa [7]
- 4(1/2)x - (3/7) = (1/4)
- 4(1/2)x = (1/4) + (3/7)
- (9/2)x = (7+12)/28
-(9/2)x = 19/28
x = (19/28) * 2 / 9
x = (19/14) / 9
x = 19 / (14*9)
x = 19 / 126
7 0
3 years ago
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