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GenaCL600 [577]
3 years ago
14

What is 15x=3y=0 written in slope-intercept form?

Mathematics
2 answers:
Tpy6a [65]3 years ago
7 0
<span>15x + 3y = 10. 

you have to solve for y. 
isolate the variable. 
15x + 3y = 10 
start by subtracting 15x on both sides. 
3y = -15x +10 
then divide both sides by 3 
y = -15/3x + 10/3 
simplify. 
y = -5x + 10/3 

10/3 can be written as 3.33 
or 3 and 1/3</span><span>
</span>
Troyanec [42]3 years ago
3 0

Answer:

The slope intercept form of the equation is y=5x where, 5 is the slope of the equation.                            

Step-by-step explanation:

Given : Equation 15x-3y=0

To find : What is the equation written in slope-intercept form?

Solution :

The slope intercept form is y=mx+c

where, m is the slope and c is the y-intercept.

So, In the given equation take y to one side,

Equation 15x-3y=0

Subtract -15x both side,

15x-3y-15x=0-15x

-3y=-15x

Divide by 3 both side,

\frac{-3y}{3}=\frac{-15x}{3}

-y=-5x

Cancel the subtract sign,

y=5x

Therefore, The slope intercept form of the equation is y=5x where, 5 is the slope of the equation.

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\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^?}{8^3}=\cfrac{1}{8^8}\implies \cfrac{8^?}{8^3}=8^{-8}\implies 8^?=8^3\cdot 8^{-8}\implies 8^?=8^{3-8}\implies 8^?=8^{-5}


\bf \begin{array}{llll} \textit{if the bases are the same, for}\\ \textit{the equation to be true, the}\\ \textit{exponents must also be the same} \end{array}~\hspace{5em}?=-5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{1}{r^3}=r^{-7}\cdot r^?\implies r^{-3}=r^{-7+?}\implies \stackrel{\textit{bases are the same, so are the exponents}}{-3=-7+?\implies 4=?}

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