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Ber [7]
3 years ago
6

Solve for x. 3/7X+ 1/3x = 32X = ?​

Mathematics
2 answers:
Aneli [31]3 years ago
8 0

3/7x+1/3x=32

We move all terms to the left:

3/7x+1/3x-(32)=0

Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R

Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R

We calculate fractions

9x/21x^2+7x/21x^2-32=0

We multiply all the terms by the denominator

9x+7x-32*21x^2=0

We add all the numbers together, and all the variables

16x-32*21x^2=0

Wy multiply elements

-672x^2+16x=0

a = -672; b = 16; c = 0;

Δ = b2-4ac

Δ = 162-4·(-672)·0

Δ = 256

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ−−√=256−−−√=16

x1=−b−Δ√2a=−(16)−162∗−672=−32−1344=1/42

x2=−b+Δ√2a=−(16)+162∗−672=0−1344=0

   

   

pentagon [3]3 years ago
5 0

Answer:

Hope its help

Step-by-step explanation:

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Nesterboy [21]
Let \mathbf p(t)=(x(t),y(t),z(t)) denote the particle's position. Then its velocity is given by

\mathbf v(t)=\dfrac{\mathrm d\mathbf p}{\mathrm dt}=(x'(t),y'(t),z'(t))
\mathbf v(t)=(18t^2-18t,0,4t-4)

The speed is then given by the absolute value/magnitude/norm of the velocity function,

\|\mathbf v(t)\|=\sqrt{(18t^2-18t)^2+(4t-4)^2}
7 0
3 years ago
A car took 6 minutes to travel between two stations that are 3 miles apart find the average speed of the car in mph
Vesna [10]

Answer: 30 mph is the answer.

Step-by-step explanation:

s = 3 miles

t = 6 minutes

so,

60 minute = 1 hour

1 minute = 1/60 hour

6 minutes = 1/60 * 6 = 0.1 hour

so

average speed = s/t

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7 0
3 years ago
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If (x+k) 2 (x+2) = x² +14x²+60x+72<br> Find the value of k.<br><br> I will give brainliest
Wittaler [7]

George C.
Jul 24, 2018
(
x
+
2
)
(
x
+
6
)
2
=
0

Explanation:
Given:
x
3
+
14
x
2
+
60
x
+
72
=
0

By the rational roots theorem, any rational zeros of the given cubic are expressible in the form
p
q
for integers
p
,
q
with
p
a divisor of the constant term
72
and
q
a divisor of the coefficient
1
of the leading term.
That means that the only possible rational zeros are:
±
1
,
±
2
,
±
3
,
±
4
,
±
6
,
±
8
,
±
9
,
±
12
,
±
18
,
±
24
,
±
36
,
±
72
In addition, note that all of the coefficients are positive and the constant term is non-zero. As a result, any real zero (rational or otherwise) of this cubic must be negative.
So that leaves rational possibilities:
−
1
,
−
2
,
−
3
,
−
4
,
−
6
,
−
8
,
−
9
,
−
12
,
−
18
,
−
24
,
−
36
,
−
72
We find:
(
−
2
)
3
+
14
(
−
2
)
2
+
60
(
−
2
)
+
72
=
−
8
+
56
−
120
+
72
=
0
So
x
=
−
2
is a zero and
(
x
+
2
)
a factor:
x
3
+
14
x
2
+
60
+
72
=
(
x
+
2
)
(
x
2
+
12
x
+
36
)
Without trying any more of our "possible" zeros, we can recognise the remaining quadratic factor as a perfect square trinomial:
x
2
+
12
x
+
36
=
x
2
+
2
(
x
)
(
6
)
+
6
2
=
(
x
+
6
)
2
So the factored form of the given cubic equation can be written:
(
x
+
2
)
(
x
+
6
)
2
=
0

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3 years ago
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4 years ago
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