Y2-y1/x2-x1
4-6/10-1
-2/9 is the slope
y-y1=m(x-x1)
y-6=-2/9(x-1)
y-6=-2/9x-2/9
Multiply both sides by 9
9y-54=-2x-2
2x+9y=52
Therefore 2x+9y=52 is the equation
Answer:
Horizontal asymptote of the graph of the function f(x) = 16x/(3+x^2) is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0.
When denominator's degree (2) is higher than nominator's degree (1) then the horizontal asymptote is y=0
I believe it is D=26 Because angle F,E is equal so A,B B,C are also equal
I think it’s B but i’m not sure