Answer:
besh cornerhiiiiiiiiiiiiiiiii
Answer:
Thus, the minimum number of photons per second is 77.34
Explanation:
Light intensity, 
= 
Pupil has a diameter, d = 8.5 mm
= 8.5 x 
m
Radius of the eye, r = 4.25 x m
∴ Area of the eye, A = 
= 
= 
Let 
be the minimum number of photons.
Therefore, = x A
= 
x 
= 
W
Thus the minimum number of photons is given by
where E = 
= 
= 
Therefore, 
= 
= 77.34 photons per second
Thus, the minimum number of photons per second is 77.34
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
I believe the answer is 3.
Hope this helped you! Please follow my account, thanks!
The process of cell division, i<span>n </span>animal cells<span>, a cleavage furrow forms </span>between<span> the two forming </span>cell<span> bodies after DNA and organelles have been replicated and situated in their new </span>cell bodies. In plant cells, in place of a cleavage furrow, a cell wall begins to form down the center of the cell, separating the polar bodies. Once the cell wall is finished forming, the cell has fully separated into two, even though it shares a cell wall.
