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8_murik_8 [283]
3 years ago
12

What is the volume of 3.5 moles of oxygen gas (O2) at standard temperature and pressure (STP)?

Chemistry
2 answers:
Irina-Kira [14]3 years ago
5 0
Any Option or is this a open ended question???
aksik [14]3 years ago
5 0
3.5 moles of O2/1 * 22.3liters/1mole
Moles cancel
3.5*22.4=78.4 liters of O2 gas
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Answer:

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Explanation:

Step 1: Given data

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Step 2: Calculate the final pressure of the gas in the can

If we assume that the gas in the can behaves as an ideal gas and that the temperature remains constant, we can calculate the final pressure of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁ / V₂

P₂ = 34.5 kPa × 473 mL / 13.16 mL = 1.24 × 10³ kPa

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3 years ago
What would be the mass of a 33.5dm3 sample of O2 at STP?
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Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

{ \tt{22.4 \:  {dm}^{3}   \: \dashrightarrow \: 16 \: grams}} \\  { \tt{33.5 \:  {dm}^{3}  \:  \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\  \\  \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}

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