Answer:
1.24 × 10³ kPa
Explanation:
Step 1: Given data
- Initial pressure of the gas (P₁): 34.5 kPa
- Initial volume of the can (V₁): 473 mL
- Final pressure of the gas (P₂): ?
- Final volume of the can (V₂): 13.16 mL
Step 2: Calculate the final pressure of the gas in the can
If we assume that the gas in the can behaves as an ideal gas and that the temperature remains constant, we can calculate the final pressure of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁ / V₂
P₂ = 34.5 kPa × 473 mL / 13.16 mL = 1.24 × 10³ kPa
Answer:
• One mole of oxygen is equivalent to 16 grams.
→ But at STP, 22.4 dm³ are occupied by 1 mole.
Answer:
B
Explanation:
hope the picture helps you to understand:)
Answer:
The answer is not 9.9 i used that and got it wrong
Explanation:
