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zalisa [80]
3 years ago
8

What is a transform boundary, and how does it affect the land?

Chemistry
1 answer:
gayaneshka [121]3 years ago
6 0

Answer:

simple

Explanation:

A transform fault or transform boundary is a fault along a plate boundary where the motion is predominantly horizontal.[1] It ends abruptly where it connects to another plate boundary, either another transform, a spreading ridge, or a subduction zone.[2]

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Which of these is a chemical property?<br><br> boiling point<br> odor<br> ability to rust<br> color
NISA [10]

Answer:

ability to rust

Explanation:

i'm like 90% sure thats correct

6 0
3 years ago
From the given reactions, which process represents the bond dissociation?
Sonbull [250]

Answer:

The correct option is: Br₂--------->2 Br(g)

Explanation:

Bond dissociation is a process in which energy is applied to break a chemical bond between the atoms of a molecule to give free atoms.

In the given reaction: Br₂-------->2 Br(g)

The covalent bond in Br₂ molecule dissociates to give two moles of bromine atoms. Therefore, it is a bond dissociation reaction.

5 0
3 years ago
How many moles of electrons are required to reduce one mole of nitrogen gas (N2) to two moles of nitrogen ions (N3-)?
Makovka662 [10]
Start by writing the atoms balance:

N_{2} -\ \textgreater \  2N^{3-}

Now, determine the change of oxidation states:N_{2} has oxidation state 0, so each N has to gain 3 electrons to become N^{3-}.

That, means that you need 6 electrons to balance the charges, resulting in:

N_{2} + 6  e^{-} -\ \textgreater \  2 N_{3-}

And the answer is 6 mole of electrons.
8 0
3 years ago
Which of the following molecules can form hydrogen bonds with itself? (select all that apply.)
hichkok12 [17]
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5 0
2 years ago
A compound is found to consist of 34.5% sodium, 16.4% boron, and 48.6% oxygen. What is the empirical formula?
NARA [144]

Answer: The empirical formula is NaBO_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given:

Mass of Na= 34.5 g

Mass of B= 16.4 g

Mass of O = 48.6 g

Step 1 : convert given masses into moles.

Moles of Na =\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{34.5g}{23g/mole}=1.5moles

Moles of B =\frac{\text{ given mass of B}}{\text{ molar mass of B}}= \frac{16.4g}{11g/mole}=1.5moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.6g}{16g/mole}=3moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na = \frac{1.5}{1.5}=1

For B = \frac{1.5}{1.5}=1

For O =\frac{3}{1.5}=2

The ratio of Na: B: O= 1: 1: 2

Hence the empirical formula is NaBO_2

7 0
3 years ago
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