Answer:
Molarity = 0.202 M
7.36 g/L HCl
Explanation:
KOH + HCl ----> KCl + H2O
1 mol 1 mol
0.560mol/L *0.045L x mol/L*0.125L
0.560mol/L *0.045L = x mol/L*0.125L
x = 0.560mol/L *0.045L /0.125L= 0.2016 mol/L≈ 0.202 mol/L=0.202M HCl
M(HCl) = 1.0+35.5 = 36.5 g/mol
0.2016 mol/L*36.5 g/mol ≈ 7.36 g/L HCl
<span>0.06355391 mol
The balanced equation for the reaction is
Na2B4O7*10H2O + 2 HNO3 = 2 NaNO3 + 4 H3BO3 + 5 H2O
So for each mole of Borax to neutralize, it takes 2 moles of HNO3.
Calculate number of moles of Borax
0.2619 g / 381.372 g/mol = 0.0006867 mol
Moles of HNO3 used = 0.0006867 mol * 2 = 0.0013734 mol
Molarity is defined as moles per liter so divide the number of moles used by the volume in liters. So
0.0013734 / 0.02161 = 0.06355391 mol</span>
Answer:
A, B & C form the vertices of a triangle.
∠ CAB = 90°, ∠ ABC = 73° and AB = 9.4.
Calculate the length of BC rounded to 3 SF
In BaF₂ the solubility will decreases on adding NaF
the solubility will increases on adding HCl
<h3>SOLUBILITY OF BARIUM FLUORIDE</h3>
- Increase in temperature will increase the solubility of the solid.
- By adding NaF - decrease the solubility of BaF₂
- By adding HCl - increase the solubility of BaF₂
<h3>BARIUM FLUORIDE</h3>
- It is colourless solid that occur as rare mineral
- It is corroded by moisture
- It is used in window of IR spectroscopy
Hence the barium fluoride the solubility decreases on adding NaF and increases on adding HCl.
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