Answer:We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.

mass of Xenon (Xe) = 5.08 g

mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g

Determine the number of moles of each of the element in the compound.

moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe

moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F

The empirical formula is therefore,

Xe(0.0387)F(0.232)

Dividing the numerical coefficient by the lesser number.

XeF₆

Explanation:

6 0

3 years ago

I heat 100. grams of water from a temperature of 10.0°C to a temperature of 50.0°C. The specific heat capacity of water is 4.18

mezya [45]

Answer:

=100×4,18×40

=16'720Joules

5 0

2 years ago

Predict the products of the reaction below. That is, complete the right hand side of the chemical equation. Be sure your equatio

pickupchik [31]

Answer:

2 HClO₃ + Ca(OH)₂ ---> Ca(ClO₃)₂ + 2 H₂O

Explanation:

This is a double-displacement reaction. In these reactions, the cation of one molecule swaps with the cation of another.

In this case, the hydrogen cation (H⁺) from HClO₃ swaps with the calcium cation (Ca²⁺) of Ca(OH)₂. When writing the products, keep the charges of the ions in mind. The products must be neutral, so some will need to have more than 1 cation/anion.

The unbalanced equation:

HClO₃ + Ca(OH)₂ ---> Ca(ClO₃)₂ + H₂O

Reactants: 3 hydrogen, 1 chlorine, 5 oxygen, 1 calcium

Products: 2 hydrogen, 2 chlorine, 7 oxygen, 1 calcium

The balanced equation:

2 HClO₃ + Ca(OH)₂ ---> Ca(ClO₃)₂ + 2 H₂O

Reactants: 4 hydrogen, 2 chlorine, 8 oxygen, 1 calcium

Products: 4 hydrogen, 2 chlorine, 8 oxygen, 1 calcium

4 0

2 years ago