¿Por que un gas no tiene sabor?

Amino acids are nothing but a basic structure which has a central atom called the "alpha carbon atom". This $\alpha$ carbon atom is bonded to an "amino group" ( $NH_{2}$ ), a "carboxyl group" (COOH) or a "hydrogen atom".

There are totally "20 types" of amino acids having a central atom bonded from the R-group. For example: When the R-group is hydrogen, then the amino acid is named glycine. Similarly, if it is attached to methyl group, then the amino acid is alanine. This makes the amino acids unique.

8 0

2 years ago

The solubility of sodium hydrogen carbonate in water 20 degrees is 9.6 g/100 g h2o.

d1i1m1o1n [39]

We can see from the details below that, the value of the solution's molality is 1.14 mol/Kg.

<h3>What is solubility?</h3>

The term solubility has to do with the quantity of solute that is able to dissolve in a given quantity of solvent. We have the solubility of the sodium hydrogen carbonate in water at 20 degrees as 9.6 g/100 g h2o.

Number of moles of sodium hydrogen carbonate = 9.6 g/84 g/mol = 0.114 moles

Number of moles water = 100 g /18 g/mol = 5.55 moles

Mole fraction of sodium hydrogen carbonate is obtainable by the use of the relation;

0.114 moles/0.114 moles + 5.55 moles

= 0.02

Molality of the solution = 0.114 moles/0.1 Kg = 1.14 mol/Kg

Learn more about solubility:brainly.com/question/8591226

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6 0

2 years ago

What is the maximum mass of glucose (C6H12O6) that can be burned in 10 g of oxygen?

Dahasolnce [82]

$C_6H_{12}O_6 + 6 \ O_2 \to 6 \ CO_2 + 6 \ H_2O$
1 mole of glucose : 6 moles of oxygen

First calculate the number of moles of oxygen in 10 g:
$M=32 \ \frac{g}{mol} \\
m=10 \ g \\
n=\frac{10 \ g}{32 \ \frac{g}{mol}}=0.3125 \ mol$

1 mole of glucose reacts with 6 moles of oxygen
x moles of glucose reacts with 0.3125 moles of oxygen
$x=\frac{1 \ mol \cdot 0.3125 \ mol}{6 \ mol} = \frac{3125}{60000} \ mol= \frac{5}{96} \ mol$

Now calculate the mass of 5/96 moles of glucose.
$M=180 \ \frac{g}{mol} \\
n=\frac{5}{96} \ mol \\
m=180 \ \frac{g}{mol} \cdot \frac{5}{96} \ mol=\frac{900}{96} \ g=9.375 \ g$

The maximum mass of glucose that can be burned in 10 g of oxygen is 9.375 g.

5 0

2 years ago