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ladessa [460]
3 years ago
7

Help I need help! I have more questions and these are due Friday!

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0
2 and 2/5 hope i helped
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Please help me ! I really need it rn ! plzz !! ill mark you brainliest :3
Elenna [48]

Answer:

Circumference= 69.08

Area = 380.13

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
22222222222222+2222222222222222222
olga_2 [115]

Answer:

22222222222222+2222222222222222222

= 2222244444444444444

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

6 0
3 years ago
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Find the GCF of <img src="https://tex.z-dn.net/?f=18x%5E%7B3%7D" id="TexFormula1" title="18x^{3}" alt="18x^{3}" align="absmiddle
melamori03 [73]

18x^3 = 6x^3 *  1

30x^5 = 6x^3 * 5x^2


So GCF = 6x^3


Answer

6x^3

8 0
3 years ago
Read 2 more answers
What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the
jeyben [28]

Answer:

  diameter = m - c

Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

  (b-r) +(a-r) = c

  (a+b) -2r = c

Now, the problem statement defines the sum of side lengths as ...

  a+b = m

and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

  m -d = c

  m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

5 0
3 years ago
Evaluate 12 x (4^-2/4^-4)<br><br> A 1/4<br> B 3/4<br> C 16<br> D 192
MrMuchimi
12 ×4^4/4^2
=12×4^2
=12×16
=192
7 0
3 years ago
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